The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
Answer:
-3 f
ithink
Step-by-step explanation:
The experimental probability is the number of specific outcomes divided by the sample size...
P(6)=27/100 (27%)
P(H)=41/100 (41%)
Not sure, but if you meant rolling a 6 AND getting a head then:
P(6 AND H)=(27/100)(41/100)=1107/10000 (11.07%)
slope = m = 16-10 / 8-5 = 6/3 = 2
y - y1 = m x (x-x1)
y-10 = 2 x (x-5)
y-10 = 2x-10
y = 2x
So,
Obviously, the car will travel 70 miles in one hour. So after one hour, the car will have traveled 70 miles. That leaves 18 miles.
The time it will take for the car to go another 18 miles will be 18 divided by 70.

Simplify.



Divide.
≈ 0.25714
So a car traveling at 70 mph will take approximately 1.25714 hours or 1.26 hours to travel 88 miles.