The sales was increased by 44.4%.
Step-by-step explanation:
- Lets do this cumulative
- 90 of 10 % = 9 which is 99
- 90 of 10 % = 9 which is 108
- 90 of 10% = 9 which is 117
- 90 of 10% = 9 which is 126
- 90 of 4 % = 3.6 which is 129.6
- 90 of 0.044% = 0.0396 which is 129.99
- This comes to nearly 44.44 to be closer there was an increase.
- Always rule 1 approximation use 50% of 90 if it is above 130.
- Down it to 40% of 90 see if the sales is lower than 130.
- It should always start with 50,40,30....10 percents.
- Alternative should be 10,1 or decimals.
- Approximation using decimals rounding up becomes simple.
Answer:
Here's what I get
Step-by-step explanation:
The formula for a quadratic equation is
ax² + bx + c = 0
The quadratic formula gives the roots:
D is the discriminant.
It tells us the number of roots to the equation — the number of times the graph crosses the x-axis.
It doesn't matter if the graph opens upwards or downwards.
If D > 0, the graph crosses the x-axis at two points.
If D = 0, the graph touches the x-axis at one point.
If D < 0, the graph never reaches the x-axis.
Your graph must look like one of the two graphs on the right in the Figure below.
Answer:
1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25
Step-by-step explanation:
We have three conditions
(1) 5P = 3S
(2) S = C + 0.30
(3) P = C – 0.20 Substitute (3) into (1)
=====
(4) 5(C – 0.20) = 3S Substitute (2) into (4)
5(C – 0.20) = 3(C + 0.30) Remove parentheses
5C – 1.00 = 3C + 0.90 Add 1.00 to each side
5C = 3C + 1.90 Subtract 3C from each side
2C = 1.90 Divide each side by 2
C = $0.95 Substitute C into Equation (2)
=====
S = 0.95 + 0.30
S = $1.25 Substitute C into Equation (3)
=====
P = 0.95 – 0.20
P = $0.75
1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25
I think it is 8,4 let me now if it is right
