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Dovator [93]
3 years ago
13

Line segment AB has endpoints A(1, 4) and B(2, 8) . A dilation, centered at the origin, is applied to AB¯¯¯¯¯ . The image has en

dpoints A′(18, 12) and B′(14, 1) . What is the scale factor of the dilation? 1/8 1/2 2 8
Mathematics
2 answers:
Kruka [31]3 years ago
8 0

Answer:

The answer is 1/8!

Step-by-step explanation:

I took the test and got this question correct! Good luck everyone, you'll do great! Especially with this correct answer =)

kumpel [21]3 years ago
7 0
To determine the scale factor of the dilation, we determine the distances between the endpoints of the two lines through the equation,
                            d = √(x₂ - x₁)² + (y₂ - y₁)²
 Substituting the known values.

Line Segment 1:     d = √(1 - 2)² + (4 - 8)²  = 4.123

Line Segment 2:     d = √(18 - 14)² + (12 - 1)² = 11.70

Dividing the answers will give us 0.352
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olga nikolaevna [1]

Answer:

i think its 10:00am

Step-by-step explanation:

6 0
3 years ago
Which equation is the direct variation equation if f(x) varies directly with x and f(x)=-18 when x=3
Otrada [13]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  \stackrel{f(x)}{y}=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=-18\\
x=3
\end{cases}\implies -18=k3
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\cfrac{-18}{3}=k\implies -6=k\qquad therefore\qquad \boxed{\stackrel{f(x)}{y}=-6x}
5 0
2 years ago
Solve for x. Show your work.<br><br> 34x-5 = (1/27) 2x+10
Ilia_Sergeevich [38]

Answer:The answer in a fraction is 405/916 and the decimal form is 0.44213973

…

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Someone please help !! I don’t know what I’m doing with this !!
dimulka [17.4K]

Answer:

  a) d(sinh(f(x)))/dx = cosh(f(x))·df(x)/dx

  b) d(cosh(f(x))/dx = sinh(f(x))·df(x)/dx

  c) d(tanh(f(x))/dx = sech(f(x))²·df(x)/dx

  d) d(sech(4x+2))/dx = -4sech(4x+2)tanh(4x+2)

Step-by-step explanation:

To do these, you need to be familiar with the derivatives of hyperbolic functions and with the chain rule.

The chain rule tells you that ...

  (f(g(x)))' = f'(g(x))g'(x) . . . . where the prime indicates the derivative

The attached table tells you the derivatives of the hyperbolic trig functions, so you can answer the first three easily.

__

a) sinh(u)' = sinh'(u)·u' = cosh(u)·u'

For u = f(x), this becomes ...

  sinh(f(x))' = cosh(f(x))·f'(x)

__

b) After the same pattern as in (a), ...

  cosh(f(x))' = sinh(f(x))·f'(x)

__

c) Similarly, ...

  tanh(f(x))' = sech(f(x))²·f'(x)

__

d) For this one, we need the derivative of sech(x) = 1/cosh(x). The power rule applies, so we have ...

  sech(x)' = (cosh(x)^-1)' = -1/cosh(x)²·cosh'(x) = -sinh(x)/cosh(x)²

  sech(x)' = -sech(x)·tanh(x) . . . . . basic formula

Now, we will use this as above.

  sech(4x+2)' = -sech(4x+2)·tanh(4x+2)·(4x+2)'

  sech(4x+2)' = -4·sech(4x+2)·tanh(4x+2)

_____

Here we have used the "prime" notation rather than d( )/dx to indicate the derivative with respect to x. You need to use the notation expected by your grader.

__

<em>Additional comment on notation</em>

Some places we have used fun(x)' and others we have used fun'(x). These are essentially interchangeable when the argument is x. When the argument is some function of x, we mean fun(u)' to be the derivative of the function after it has been evaluated with u as an argument. We mean fun'(u) to be the derivative of the function, which is then evaluated with u as an argument. This distinction makes it possible to write the chain rule as ...

  f(u)' = f'(u)u'

without getting involved in infinite recursion.

7 0
2 years ago
Sally has Christmas lights the roof is 16 feet high the ladder is 20 ft long how far away is letter from wall
lesantik [10]
It should be 12 ft away from the wall. Not 4 ft. You do not just subtract the difference because as you pull it away from the wall, the ladder is mostly moving horizontally with only a small vertical change.

You can use Pythagorean Theorem to find the answer. Think of the ladder as the hypotenuse of a right triangle with the wall and the ground as the legs.

a^2 + b^2 = c^2

16^2 + b^2 = 20^2

b^2 = 20^2 - 16^2

b^2 = 144

b = 12 ft






4 0
3 years ago
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