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Norma-Jean [14]
3 years ago
15

81x^2-72x+16 is a perfect square trinomial. TRUE OR FALSE ?

Mathematics
1 answer:
dangina [55]3 years ago
6 0
True true true........
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Use long division to determine the quotient of the polynomials. (x3 – 7x – 6) ÷ (x – 4) Which of the following options best desc
Lelechka [254]

Answer:

The correct option is c.

Step-by-step explanation:

The quotient of the polynomials is

\frac{(x^3-7x-6)}{x-4}

We need to find the remainder by using long division method.

The dividend of the given expression is

Dividend=x^3-7x-6

Divisor=x-4

The long division method is shown below.

\frac{(x^3-7x-6)}{x-4}=(x^2+4x+9)+\frac{30}{x-4}

From the below attachment it is clear that the quotient has a remainder of 30. Therefore, the divisor is not factor of the dividend.

Therefore the correct option is c.

4 0
3 years ago
Select the correct answer. Which expression is equivalent to 8x^2^3 sqrt 375x + 2^3 sqrt 3x^7, if x=0?
natima [27]

Answer:

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}

Step-by-step explanation:

The question is poorly formatted. The original question is:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

We have:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

Open bracket

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

Express 8 as 2^3

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^{3* \frac{2}{3}} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^2 *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

Express 2^3 as 8

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{75x^3} + 8\sqrt{ 3x^7}

Expand each exponent

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2 *3x} + 8\sqrt{ 3x * x^6}

Split

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2} *\sqrt{3x} + 8\sqrt{3x} * \sqrt{x^6}

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =4x^2 *5x *\sqrt{3x} + 8\sqrt{3x} * x^3

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =20x^3\sqrt{3x} + 8x^3\sqrt{3x}

Factorize

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}

4 0
3 years ago
Read 2 more answers
Mrs. Nicholas baked two batches of cookies. The first batch consisted of 120 gingerbread cookies and the second batch consisted
shusha [124]

Answer:

i think 2/15 of the cookies

Step-by-step explanation:

hope this helps

3 0
1 year ago
ANSWER FOR BRAINLIEST AND EXPLAIN!! :)
KengaRu [80]

Answer:

x = 6

Step-by-step explanation:

All triangle angles add up to 180 so:

90 + 5x + 6 + 54 = 180

5x + 150 = 180

5x = 30

x = 6

7 0
3 years ago
Read 2 more answers
Find the value of x.
Anna [14]

Answer:

55.7°

Step-by-step explanation:

I hope this helps.

7 0
3 years ago
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