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Nadusha1986 [10]
3 years ago
8

Please help with this math work.

Mathematics
1 answer:
Musya8 [376]3 years ago
4 0
What is the questionnn
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Y=2(x+4)^2-21<br><br> Convert the equation from vertex form to standard
PSYCHO15rus [73]

Answer:

y = 2x² + 16x + 11

I hope im right... If not reaaally sorry!!

7 0
3 years ago
20. Rewrite the following expression as a fraction times the variable.<br> -8a/9
Schach [20]

Answer:

-8a times 1/9

Step-by-step explanation:

This can be thought of as -8a/1 times 1/9. (1/9 is the reciprocal of 9, so were just pulling the fraction apart)

8 0
3 years ago
Ms. Reynolds has a system of 10 sprinklers that water her entire lawn. The sprinklers run one at a time, and each runs for the s
Flauer [41]
You are told that sprinklers run for the same amount of time. lets refer to this time as T.
you are told that 4 sprinkles run one at a time for 50 minutes total. that means that T should be 50/4 = 12.5 minutes = 12 minutes and 30 seconds
3 0
3 years ago
Prove this trigonometric equation;<br><br> - tan^2x + sec^2x = 1,
alekssr [168]
Hey there :)

- tan²x + sec²x = 1    or    1 + tan²x = sec²x

sin²x + cos²x = 1 
Divide the whole by cos²x

\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}

\frac{sinx}{cosx} = tanx so \frac{sin^2x}{cos^2x} = tan^2x
and
\frac{1}{cosx} = secx so \frac{1}{cos^2x} = sec^2x

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0
2 years ago
Find the length of the hypotenuse of a triangle if one of its legs is 11 cm long and its perimeter is 132 cm.
rodikova [14]

Answer:

1.)

132 cm - 11 cm = 121 cm

So let the hypotenuse be x and the other leg be (121 - x).

11^2 + (121 - x)^2 = x^2

121 + 121^2 - 121(2)x = 0

x = 1/2 + 121/2 = 61 cm

Step-by-step explanation: not sure if this is right or not

7 0
3 years ago
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