3 years ago

Please help with this math work.

Mathematics

1 answer:

Musya8 [376]3 years ago

4 0

What is the questionnn

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Y=2(x+4)^2-21 Convert the equation from vertex form to standard

PSYCHO15rus [73]

Answer:

y = 2x² + 16x + 11

I hope im right... If not reaaally sorry!!

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3 years ago

20. Rewrite the following expression as a fraction times the variable. -8a/9

Schach [20]

Answer:

-8a times 1/9

Step-by-step explanation:

This can be thought of as -8a/1 times 1/9. (1/9 is the reciprocal of 9, so were just pulling the fraction apart)

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3 years ago

Ms. Reynolds has a system of 10 sprinklers that water her entire lawn. The sprinklers run one at a time, and each runs for the s

Flauer [41]

You are told that sprinklers run for the same amount of time. lets refer to this time as T.
you are told that 4 sprinkles run one at a time for 50 minutes total. that means that T should be 50/4 = 12.5 minutes = 12 minutes and 30 seconds

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3 years ago

Prove this trigonometric equation; - tan^2x + sec^2x = 1,

alekssr [168]

Hey there :)

- tan²x + sec²x = 1 or 1 + tan²x = sec²x

sin²x + cos²x = 1
Divide the whole by cos²x

$\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}$

$\frac{sinx}{cosx} = tanx$ so $\frac{sin^2x}{cos^2x} = tan^2x$
and
$\frac{1}{cosx} = secx$ so $\frac{1}{cos^2x} = sec^2x$

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0

2 years ago

Find the length of the hypotenuse of a triangle if one of its legs is 11 cm long and its perimeter is 132 cm.

rodikova [14]

Answer:

1.)

132 cm - 11 cm = 121 cm

So let the hypotenuse be x and the other leg be (121 - x).

11^2 + (121 - x)^2 = x^2

121 + 121^2 - 121(2)x = 0

x = 1/2 + 121/2 = 61 cm

Step-by-step explanation: not sure if this is right or not

7 0

3 years ago