All categories

3 years ago

Sketch the curve y=x(x-2)^3 showing any stationary points and points of inflection

Mathematics

2 answers:

ycow [4]3 years ago

6 0

Answer:

hshsnwjsbsbskakdbdbsn

elixir [45]3 years ago

3 0

Answer:

Step-by-step explanation:

hello :

let : y=f(x)

f(x)==x(x-2)^3 so : f'(x) = 1.(x-2)^3+3x(x-2)²

f'(x) = (x-2)²(x-2+3x)

f'(x) = (x-2)²(4x-2)

f'(x) =0 : x=2 or x=1/2

the minumum is (1/2 ,f(2))

the inflection points use f"(x) = 0.......continu

You might be interested in

Find the slope of the line that passes through the given points.<br> (7,3) and (13,8)

Trava [24]

Answer:

$\frac{5}{6}$

Step-by-step explanation:

To find the slope, use the equation to find slope. The picture below shows what it looks like.

Using the equation, substitute the values in the x and y values.

$\frac{8-3}{13-7}$

Then solve

$\frac{5}{6}$

4 0

3 years ago

Evaluater 3/7+ 5/8s when r =14s =8.

adell [148]

Answer:

Step-by-step explanation:

Alright, lets get started.

The given expression as :

$\frac{3}{7}r + \frac{5}{8}s$

r is given as 14 and s is given as 8

Plugging the value of r and s in given expression.

$\frac{3}{7}(14) + \frac{5}{8}(8)$

$3*2 + 5$

$6+5$

$11$

Hence the answer is 11 : Answer

Hope it will help :)

3 0

2 years ago

Please I need a quick reply

Rom4ik [11]

Answer:

Step-by-step explanation:

It sounds most likely to the right answer

¯\_(ツ)_/¯

4 0

2 years ago

Read 2 more answers

I need someone to solve this problem for me please

Amiraneli [1.4K]

First, solve the area of the entire large rectangle (28)(45) = 1260
Next, find the area of the chunk that is cut out (11)(15) = 165
- we know the width is 15 because 45 - 6 - 24
Subtract the cut out piece from the overall rectangle 1260 - 165 = 1095

7 0

3 years ago

Read 2 more answers

Find an equation for the linear function g(x) which is perpendicular to the line 5x-2y=6 and intersects the line 5x-2y=6 at x=12

exis [7]

Answer:

≡

Step-by-step explanation:

8 0

2 years ago