3 years ago

Sketch the curve y=x(x-2)^3 showing any stationary points and points of inflection

Mathematics

2 answers:

ycow [4]3 years ago

6 0

Answer:

hshsnwjsbsbskakdbdbsn

elixir [45]3 years ago

3 0

Answer:

Step-by-step explanation:

hello :

let : y=f(x)

f(x)==x(x-2)^3 so : f'(x) = 1.(x-2)^3+3x(x-2)²

f'(x) = (x-2)²(x-2+3x)

f'(x) = (x-2)²(4x-2)

f'(x) =0 : x=2 or x=1/2

the minumum is (1/2 ,f(2))

the inflection points use f"(x) = 0.......continu

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