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3 years ago

I need help with finding the arc measure of this problem.

Mathematics

1 answer:

Leto [7]3 years ago

4 0

Answer:

180+69=249

I got 180 from the ABC, that is half the circle then + the 69

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Let f(x) = xe^-x+ ce^-x, where c is a positive constant. For what positive value of c does f have an absolute

Illusion [34]

Answer:

$c=6$

Step-by-step explanation:

The absolute maximum of a continuous function $f(x)$ is where $f'(x)=0$ . Therefore, we must differentiate the function and then set $x=-5$ and $f'(x)=0$ to determine the value of $c$ :

$f(x)=xe^{-x}+ce^{-x}$

$f'(x)=-xe^{-x}+e^{-x}-ce^{-x}$

$0=-(-5)e^{-(-5)}+e^{-(-5)}-ce^{-(-5)}$

$0=5e^{5}+e^{5}-ce^{5}$

$0=e^5(5+1-c)$

$0=6-c$

$c=6$

Therefore, when $c=6$ , the absolute maximum of the function is $x=-5$ .

I've attached a graph to help you visually see this.

7 0

3 years ago

A bakery is filling an order for 180 cupcakes. Jeff has baked and

REY [17]

Answer:

135 cupcakes

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

PLEASEEEE HELP ME ITS FOR AN IMPORTANT TEST AND I WAS NOT PAYING ATTENTION LOL

hichkok12 [17]

Answer: 3^2 * 3^8

Step-by-step explanation: 3^(4-2) * 3^(5+3)

3 0

3 years ago

Read 2 more answers

There are 32 students in a class. Of the class, 3/8 of the students bring their own lunches. How many students bring their lunch

OverLord2011 [107]

Answer:

The number of students that bring their lunches is 12

Step-by-step explanation:

Let

x -----> the number of students that bring their lunches

y -----> the total number of students in a class

we know that

The number of students that bring their lunches divided by the total number of students in a class must be equal to 3/8

$\frac{x}{y}=\frac{3}{8}$

$x=\frac{3}{8}y$ -----> equation A

$y=32$ -----> equation B

substitute the value of y in equation A and solve for x

$x=\frac{3}{8}(32)$

$x=12$

therefore

The number of students that bring their lunches is 12

6 0

3 years ago

In a group of 60 students, 18 students take algebra i, 20 students take algebra ii, and 10 students take both subjects. how many

nadya68 [22]

Answer:

Step-by-step explanation:

The number that take algebra i includes those who take both subjects, as does the number taking algebra ii. Then the number taking algebra i alone is ...

18 -10 = 8 . . . . . take only algebra i

So the number taking any kind of algebra is ...

20 + 8 = 28

and the number not taking either subject is ...

60 -28 = 32 . . . not taking either subject

8 0

3 years ago