Answer:
Only points on the circle satisfy the given inequality.
Step-by-step explanation:
Given: Unit circle
To find: portion of the unit circle which satisfies the trigonometric inequality 
Solution:
In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)
= side opposite to
/hypotenuse
= side adjacent to
/hypotenuse


So, coordinates of A = 
For any point (x,y) on the unit circle with centre at origin, equation of circle is given by 
Put 

So,
satisfies the equation 
For points
inside the circle, 
For points
outside the circle, 
So, only points on the circle satisfy the given inequality.