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jok3333 [9.3K]
3 years ago
8

If 1 yard = 3 feet and 1 mile = 5,280 feet, how many yards are there in 1miles?

Mathematics
1 answer:
slavikrds [6]3 years ago
8 0

1 yard = 3 feet

1 mile = 5,280 feet

So, 1 mile = 5,280/3 yards = 1760 yards

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What is the sum of the measures of the interior angle formed by the boundary of this team pennant
Elis [28]
180 because it is a triangle
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2 years ago
Julie cashed a paycheck and repaired her brother $10 that she borrowed from him. She then spent $30 on fuel for her car and half
pochemuha
Remark
She starts out with x
She spends 10 dollars paying back her brother (that's - 10)
She spends 30 dollars on fuel (that - 30)
She spends 1/2 what's left on a tent ( that's 1/2 (x - 10 - 30) )
She then spent 29.45  on running shoes. 1/2 (x - 10 - 30) + 29.45 is her expenditures.

After all that she has 17.75 left. 

Equation
x - 10 - 30 - 1/2(x - 10 - 30) - 29.45 = 17.75   

Solve
Begin by adding 29.95 to both sides. 
x - 10 - 30 - 1/2(x - 10 - 30)  = 17.75 + 29.45 
x -10 - 30 - 1/2(x - 10 - 30)  = 47.20  Add the like terms on the left.
x - 40 - 1/2(x - 40) = 47.20 Add 40 to both sides. Don't go inside the brackets.
x - 1/2x + 1/2 (40) = 87.20
1/2 x + 20 = 87.20                        Subtract 20 from both sides.
1/2 x = 67.20                                Multiply by 2
x = 134.40 


3 0
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Read 2 more answers
Students collected data about the capacities of their lungs by inflating balloons with a single breath. they measured the circum
marishachu [46]
The given data is the following:

Student Trial 1  Trial 2 Trial 3 Average
-----------  --------  --------  --------  ------------
    1           66.0    66.5   68.5     67.0
    2          67.5     64.0   70.5     67.3
    3          60.3     60.5   60.5    61.0
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Let us check the reported averages.
Student 1:
Average = (66.0 + 66.5 + 68.5)/3 = 67.0   Correct
Student 2:
Average = (67.5 + 64.0 + 70.5)/3 = 67.3    Correct
Student 3:
Average = (60.3 + 60.5 + 60.5)/3 = 604    Incorrect
Student 4:
Average = (55.0 + 58.0 + 59.0)/3 = 57.3    Correct

Answer: Student 3
6 0
3 years ago
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In 2008, the average household debt service ratio for homeowners was 13.2. The household debt service ratio is the ratio of debt
ankoles [38]

Answer:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

df=n-1=44-1=43  

p_v =P(t_{(43)}>1.436)=0.079  

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

Step-by-step explanation:

Information given

\bar X=13.88 represent the sample mean

s=3.14 represent the sample standard deviation

n=44 sample size  

\mu_o =13.2 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to conduct a hypothesis in order to check if the true mean has increased from 2008 , and the system of hypothesi are:  

Null hypothesis:\mu \leq 13.2  

Alternative hypothesis:\mu > 13.2  

The statistic for this case is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculating the statistic

Replacing the info given we got:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

P-value

The degrees of freedom are:

df=n-1=44-1=43  

Since is a right tailed test the p value is:  

p_v =P(t_{(43)}>1.436)=0.079  

Decision

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

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Answer:

45 is um 9x+xy-4y

Step-by-step explanation:

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