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disa [49]
3 years ago
11

Pls list out the steps

Mathematics
1 answer:
Daniel [21]3 years ago
5 0
First, the bigger square's area is 20*20= 400 cm^2

second, the circle's area is ¶r^2 = ¶(20/2)^2 = ¶(10)^2 = 100¶ cm^2

third, smaller square-- if we imagine it as 4 parts as 4 right triangles-- 1 part will be 1/2*(20/2)(20/2) = 1/2 (10)(10) = 50 cm^2 then the area of the smaller square is 4*50 = 200 cm^2

so the shaded parts = circle - smaller square =100¶ - 200 cm^2

the answer is 2

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What is the y-intercept of the line y + 6 = -4(X - 1.5)
Rudiy27

Answer:

y=0.

y + 6 = -4(X - 1.5)

y+6 = -4x+6

y = mx+b

y=4x

There isn't a b, which is the y intercept, so the y int would be 0

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3 years ago
On avarage kayla drinks 3/4 of an 6 ounce glass of water 1/6 of an hour.How much water does she drink, in glasses per hour?
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Step-by-step explanation:

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Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
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Store B, since they are two for 4.20$ while Store A has only ONE for 3.00$ meaning let’s say we’re gonna buy two packs it would be 4.20$ for Store B and 6.00$ for Store A
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Answer:

-32000x^2

Step-by-step explanation:

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