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3 years ago

Round 3.392 to the nearest whole number

Mathematics

2 answers:

Gnoma [55]3 years ago

8 0

The nearest number is 4

Ber [7]3 years ago

6 0

Round 3.392 to the nearest whole number
ANSWER--> 3.5

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Need help with a math question

krek1111 [17]

Answer:

x=13°

Step-by-step explanation:

If BE is an angle bisector, then it divides the angle into two equal angles. This means that

∠ABE=∠EBC

Since ∠ABE=2x+20 and ∠EBC=4x-6, we have

2x+20=4x-6

2x-4x=-6-20

-2x=-26

2x=26

x=13°

4 0

3 years ago

Help me plz thanks my friend

NikAS [45]

Answer:

I believe the answer would be 21.

Step-by-step explanation:

the shadow of the tall flag is three times the small flag, so the height of the flag should also be three times the height. which is 21

6 0

2 years ago

HELP I DONT UNDERSTAND :(

dsp73

Answer:

{ 100, 125,150,175}

Step-by-step explanation:

The range is the output values

{ 100, 125,150,175}

5 0

3 years ago

Use the drawing tool(s) to form the correct answers on the provided graph.

lianna [129]

Answer:

see below

Step-by-step explanation:

A graphing calculator can help you do this.

The function crosses the y-axis where x=0.

g(0) = -5^0 +5 = -1 +5

g(0) = 4

The function crosses the x-axis where g(x) = 0

0 = -5^x +5

5^x = 5 = 5^1

x = 1

g(1) = 0

The points of interest are (0, 4) and (1, 0).

7 0

3 years ago

If x = a cosθ and y = b sinθ , find second derivative

Olin [163]

I'm guessing the second derivative is for y with respect to x, i.e.

$\dfrac{\mathrm d^2y}{\mathrm dx^2}$

Compute the first derivative. By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta$

$x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta$

Now compute the second derivative. Notice that $\frac{\mathrm dy}{\mathrm dx}$ is a function of $\theta$ ; so denote it by $f(\theta)$ . Then

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}$

By the chain rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$f=-\dfrac ba\cot\theta\implies\dfrac{\mathrm df}{\mathrm d\theta}=\dfrac ba\csc^2\theta$

and so the second derivative is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac ba\csc^2\theta}{-a\sin\theta}=-\dfrac b{a^2}\csc^3\theta$

4 0

3 years ago