F(x) = x - 2sinx
To find for what values of x graph has tangents we need to differentiate function f(x).
f'(x) = 1-2cosx
Now, if we want to have horizontal tangents we need to make function f'(x) equal to 0 because at minimum or maximum of function f(x) tangent is horizontal.
1-2cosx = 0
cosx = 1/2
x = pi/3 + 2*n*pi and
x = -pi/3 + 2*n*pi
Explanation: cosx = 1/2 for both 60° and -60°. If we make one circle cosx will be equal to 1/2 for 420 and 300 degrees. Writing degrees in radians (using pi) we can write formulas above where 2*pi represents one full circle and n is an integer which represents how many circles we made.
75 watch balloons filled in 40 mins
It will be Ac because aB goes after Ac
Answer:
y=2x+8
Step-by-step explanation:
Alright so, to find the equation, we need to find the slope first. We can do that by turning the input and output into coordinates.
(1,10) and (2,12)
To find the slope, we do:

Which equals to 2
So right now we can say that the equation is:
y=2x+b
In order to find b, the constant, we just need to plug in the y values and x value of a coordinate:
10=2(1)+b
10=2+b
8=b
So now we can say that the equation is:
y=2x+8
(x^m) times (x^n)=x^(m+n)
(1/8)^5 times (1/8)^3=(1/8)^(5+3)=(1/8)^8=1/(8^8)