Question

Find the approximate solution of this system of equations. y=x^2+5x+3 y=square root2x+5

Answer 1

We have that
y=x²+5x+3
y=√(2x+5)

using a graph tool
see the attached figure

the solution is 
x=-0.175
y=2.156

therefore

the answer is the option
B.) (-0.2, 2.1)

Answer 2

Answer:

$x=-1.216 and x= -0.175$

Step-by-step explanation:

Given is a system of equations in x. One quadratic and other square root.

1) $y=x^2+5x+3$

2) $y=\sqrt{2x+5}$

Subtracting 2 from 1 we get

$x^2+5x+3=\sqrt{2x+5}$

Square both the sides

$x^4+25x^2+9+10x^3+30x+6x^2 =2x+5\\x^4+10x^3+31x^2+28x+4=0$

We find that there are only two real roots and they are approximately

x=-1.216 and x= -0.175