Answer:
- boat speed: 17.25 mph
- current: 2.5 mph
Step-by-step explanation:
Upstream, the speed of the current (c) subtracts from the speed of the boat (b) to give the net speed. Downstream, the speed of the current adds. We can make use of the relation ...
speed = distance/time
b-c = 29.5/2 = 14.75 . . . . . miles/hour
b+c = 59.25/3 = 19.75 . . . .miles/hour
Subtracting the first equation from the second, we get ...
(b+c) -(b-c) = 19.75 -14.75
2c = 5
c = 2.5
Then either equation can be used to find b:
b = 14.75 +c = 17.25
The speed of the boat in still water is 17.25 miles per hour; the speed of the current is 2.5 miles per hour.
Answer:
They are all real numbers.
Option (2) and (5) I think is correct. x = -5 and x = 3
Step-by-step explanation:
Answer: Option (2) and (5) is correct. ... We have to find the solution of the given equation (x + 5)(x – 3) = 0 and choose the correct option from the given·
It’s tells me that the line started at coordinate (0,39)
Let's begin by calling Sarah's age now as X. As Ralph is 3 times as old as Sarah, X times 3 = 3X. Hence, Ralph's age is 3X. In six years, Ralph will be twice as old as Sarah. To calculate six years from now, add 6 to X for Sarah, and 6 to 3X for Ralph. As Ralph is twice as old as Sarah and we want to find the difference between the ages to calculate X, multiply X+6 by 2. You'll get 2X+12. Therefore, 2X+12=3X+6. Deduct 6 from 3X+6 as we want to isolate the variable. Because you did that to one side, you have to deduct 6 from 2X+12. Hence, now you have 2X+6=3X. X=6. Ralph's age is 3X, so 6 times 3 is 18. Ralph is 18 years old.
The fraction between 1/2 and 2/2 is 1/4
