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3 years ago

5

The apartment you like rents for $700 a month. The landlord requires two months’ rent for the security deposit. How much is the

security deposit?

1 answer:

Vlada [557]3 years ago

6 0

Answer: 1400.00

Step-by-step explanation:

You might be interested in

A nutrition lab tested 40 hot dogs to see if their mean sodium content was less than the 325-mg upper limit set by regulations f

tekilochka [14]

Answer:

Step-by-step explanation:

Given that a nutrition lab tested 40 hot dogs to see if their mean sodium content was less than the 325-mg upper limit set by regulations for "reduced sodium" franks

90% confidence interval is

(317.2, 326.8)mg.

Using confidence intervals,we can check whether null hypothesis is true.

Here

$H_0: \bar x = 325\\H_a: \bar x$

(left tailed test at 10% significance level)

We check whether confidence interval 90% contains the mean value.

We find 325 belongs to the confidence interval

Hence H0 is true

The hot dogs do not satisfy.

4 0

4 years ago

Which function is equivalent to f(x)=-4(x+7)^2-6

Bess [88]

Pls mark Brainliest.

Answer:

f(x) = -4x² - 64x - 202

Step-by-step explanation:

We can simplify this quadratic function given in vertex form into standard form by simplifying the exponents and adding like terms.

f(x) = -4(x+7)^2 - 6

f(x) = -4(x^2 + 14x + 49) - 6

f(x) = -4x² - 64x - 196 - 6

f(x) = -4x² - 64x - 202

5 0

3 years ago

If the fraction 6/10 equals 0.6,then 2/10 equals

Mila [183]

Answer:

0.2

Step-by-step explanation:

2/10=1/5=0.2

hope this helps

5 0

4 years ago

Read 2 more answers

Find the differential of each function. (a) y = tan( 5t ) dy = Correct: Your answer is correct. (b) y = 5 − v2 5 + v2

Trava [24]

Answer:

$(a)$ $dy = 5sec^2(5t) \ dt$

$(a) \ dy = \frac{-20v}{(5+v^2)^2} \ dt$

Step-by-step explanation:

Given;

(a) y = tan(5t)

$(b) \ y = \frac{5-v^2}{5+v^2}$

Solving for (a)

y = tan(5t)

let u = 5t

⇒y = tan(u)

du/dt = 5

dy/du = sec²u

$\frac{dy}{dt} =\frac{dy}{du} *\frac{du}{dt} \\\\\frac{dy}{dt} = sec^2(u)*5\\\\\frac{dy}{dt} = 5sec^2(u)\\\\\frac{dy}{dt} = 5sec^2(5t)$

$dy = 5sec^2(5t) \ dt$

Solving for b;

let u = 5 - v²

du/dv = -2v

let v = 5+ v²

dv/du = 2v

$\frac{dy}{dv} = \frac{vdu - udv}{v^2} \\\\\frac{dy}{dv} = \frac{-2v(5+v^2) - 2v(5-v^2)}{(5+v^2)^2}\\\\\frac{dy}{dv} = \frac{-10v-2v^3-10v+2v^3}{(5+v^2)^2}\\\\$

$\frac{dy}{dv} = \frac{-10v-10v}{(5+v^2)^2}\\\\\frac{dy}{dv} = \frac{-20v}{(5+v^2)^2}\\\\dy = \frac{-20v}{(5+v^2)^2} dt$

4 0

3 years ago

-2x3x simplify please

Anvisha [2.4K]

-6x is the answer hope it helps

4 0

3 years ago