we know that
m∠SQR+x= -------> by supplementary angles
so
m∠SQR=
The sum of the internal angles of a triangle is equal to degrees
m∠SQR+m∠QSR+m∠SRQ=
substitute the values in the formula
m∠SQR++
=
m∠SQR= degrees
<u>Find the value of x</u>
m∠SQR=
x=-m∠SQR
x=
x= degrees
therefore
<u>the answer is</u>
the value of x is degrees
Answer:
The equation of the circle having centre (-5,-9) and radius r=3 is
x² + 10 x +y² + 14 y + 65 = 0
Step-by-step explanation:
<u>Explanation</u>:-
From graph The centre of the circle C( -5 , -7)
The radius of the circle r = 3cm from the centre of the given circle
The equation of the circle
From graph the centre ( h, k) = ( -5,-7) and r = 3cm
x² + 10 x +25 +y² + 14 y + 49 =9
x² + 10 x +25 +y² + 14 y + 49 -9=0
The equation of the circle
x² + 10 x +y² + 14 y + 65 = 0