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Korolek [52]
3 years ago
10

What is the value of x? x = 23   x = 35 x = 58 x = 93

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
6 0
If you add the given angles they equal 93, which is the only answer that is able to be obtuse. Therefore the answer is 93. 
Akimi4 [234]3 years ago
5 0

we know that

m∠SQR+x=180 -------> by supplementary angles

so

m∠SQR=180-x

The sum of the internal angles of a triangle is equal to 180 degrees

m∠SQR+m∠QSR+m∠SRQ=180

substitute the values in the formula

m∠SQR+35+58=180

m∠SQR=87 degrees

<u>Find the value of x</u>

m∠SQR=180-x

x=180-m∠SQR

x=180-87

x=93 degrees

therefore

<u>the answer is</u>

the value of x is 93 degrees

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\displaystyle \lim_{x \to 0 } \frac{1 - \prod \limits_{k = 2}^{3} \sqrt[k]{\cos(kx)} }{ {x}^{2} }

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a^n-b^n = (a-b)\left(a^{n-1}+a^{n-2}b+a^{n-3}b^2+\cdots a^2b^{n-3}+ab^{n-2}+b^{n-1}\right)

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\displaystyle \frac{a^6-b^6}{x^2 \left(a^5+a^4b+a^3b^2+a^2b^3+ab^4+b^5\right)}

As x approaches 0, both a and b approach 1, so the polynomial in a and b in the denominator approaches 6, and our original limit reduces to

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For the remaining limit, use the Taylor expansion for cos(x) :

\cos(x) = 1 - \dfrac{x^2}2 + \mathcal{O}(x^4)

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\displaystyle \cos^3(2x) \cos^2(3x) = \left(1 - 2x^2\right)^3 \left(1 - \frac{9x^2}2\right)^2

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Lateral Surface Area = 2π×2×15 = 188.49555921539 feet2
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(Figure B)

Base Surface Area = 2π×82 = 402.12385965949 feet2
Lateral Surface Area = 2π×8×22 = 1105.8406140636 feet2
Total Surface Area = 1507.9644737231 feet2
(Figure C)


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