Brian tried to solve a math problem on his math homework. Here's one of the questions he had to answer. How do you solve 2/3p +
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If Sa=2πrh+2πv=π
then the surface area is π
and volume is
(rh-2h)/2r.
Given Sa=2πrh+2π=π
.
We have to find surface area and volume from the given expression.
Volume is basically amount of substance a container can hold in its capacity.
First we will find the value of v from the expression. Because they are in equal to each other, we can easily find the value of v.
2πrh+2πv=π
h
Keeping the term containing v at left side and take all other to right side.
2πv=π
-2πrh
v=(πh-2πrh)/2π
v=π/2π
-2πrh/2π
v=h/2-h/r
v=h(r-2)/2r
Put the value of v in Sa=2πrh+2π
Sa=2πrh+2π*h(r-2)/2r
=2πrh+2πrh(r-2)/2
=2πrh+πrh(r-2)
=2πrh+πh-2πrh
=πh
Hence surface area is πh and volume is h(r-2)/2.
Learn more about surface area at brainly.com/question/16519513
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