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3 years ago

100 POINTS AND BRAINLY

Mathematics

2 answers:

Neporo4naja [7]3 years ago

7 0

$\\ \rm\hookrightarrow cos61=\dfrac{10}{x}$

$\\ \rm\hookrightarrow x=10/cos61$

$\\ \rm\hookrightarrow x=10/0.5$

$\\ \rm\hookrightarrow x=20$

alexandr402 [8]3 years ago

3 0

Answer:

x = 20.6°

using cosine rule:

$\sf cos(x)= \dfrac{adjacent}{hypotensue}$

using the formula:

$\sf cos(61)= \dfrac{10}{x}$

$\sf x= \dfrac{10}{cos(61)}$

$\sf x= 20.6$

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Ann lives 3/10 mile from school. Carlos lives 1/10 mile from school. How much farther from school does Ann live than Carlos?

sattari [20]

3/10 - 1/10 =2/10
Thats what I think

7 0

3 years ago

Suppose your top drawer contains different colored socks: 14 are white, 4 are black, 12 are pink, and 8 are blue. All socks in t

Svetllana [295]

Answer:

8/38

Step-by-step explanation:

you calculate how many socks and then take how many the blue ones are

3 0

4 years ago

At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

8 0

3 years ago

Help me on this please

Rina8888 [55]

Answer:

x = 3.5

Step-by-step explanation:

Triangle to the right:

4^2 + x^2 = 8^2

16 + x^2 = 64

y^2 = 48

Triangle to the left:

x^2 + 6^2 = 48

x^2 + 36 = 48

x^2 = 12

x = sqrt(12)

x = 3.5

4 0

3 years ago

Given three points A(-7, 1), B(m, 6) and P(-1, n). If the point P divides AB internally in the ratio of 3: 2, find the values of

vesna_86 [32]

Answer:

m = 3 , n = 4

Step-by-step explanation:

Using Section Formula.

$If \ the \ line \ segment \ AB \ where \ A = (x _1, y_1) \ and \ B = (x_2, y_2) \ divided \ by \ P =(x , y) \ in \ the \ ratio \ a : b,\\\\Then \ the \ points \ of \ P \ \\\\x = \frac{ax_2 + bx_1}{a+b} \ and \ y = \frac{ay_2 + by_1}{a+b}$

$Here (x_1 , y_ 1 ) = ( -7 , 1 ) \ and \ (x_ 2 , y _ 2 ) = (m , 6)\\\\ratio\ a:b = 3 : 2\\\\Therefore, P (x, y) \\\\x = \frac{3m + (2\times -7)}{5} \ \ \ \ \ \ \ \ \ \ \ [ \ x = -1 \ ] \\\\-1 = \frac{3m - 14}{5}\\\\- 5 = 3m - 14\\\\-5 + 14 = 3m\\\\9 = 3m \\\\m = 3$

$y =\frac{3\times 6 + 2 \times 1}{5}\\\\n = \frac{18 + 2}{5} = \frac{20}{5} = 4$

5 0

3 years ago