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Trava [24]
3 years ago
14

Rewrite each expression as a single power ​

Mathematics
2 answers:
Readme [11.4K]3 years ago
7 0

512

-------

32

================================

Korolek [52]3 years ago
4 0

Answer:

Since they are the same base, just subtract the powers. 9-5=4. So the answer is 2 to the 4th power which can be simplified to 16

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Rick bought a pair of pants for $45.00. The sales tax rate is 8%. How much did he pay total for the pants?
Mazyrski [523]
Answer: $48.60
Get this answer by multiplying 48 by 1.08
5 0
3 years ago
9/20 in percent form​
Maru [420]

Answer:

45%

Step-by-step explanation:

9/20. 20* 5= 100. 9*5=45. 45/100=45%

8 0
3 years ago
Read 2 more answers
Evaluate the following expression using the values given: Find 2r2 + 3s3 − r2 + 4t2 − r2 if r = −2, s = −3, and t = 5. −19 −37 2
crimeas [40]
2r² + 3s³ - r² + 4t² - r² = 3s³ + 4t²
<span>if s = -3 and t = 5
</span>3s³ + 4t² = 3 * (-3)³ + 4 * 5² = 3 * (-27) + 4 * 25 = -81 + 100 = 19

Answer: 19
5 0
3 years ago
Jacqueline earned a commission of $200 for one week at work. her commission rate is 12% of the merchandise she sells. how much m
guajiro [1.7K]

For this case, the first thing we must do is define variables.

We have then:

m: original quantity of merchandise sold (in $)

We then have the following idea:

(original amount) (percent) = new amount

The new amount is the amount that Jacqueline earns for 12% of the commission on sales.

We have then:

m (0.12) = 200

Clearing m we have:

m =\frac{200}{0.12}\\m = 1666.7

  Answer:

The equation that solves the problem is:

m (0.12) = 200

The amount she sold is:

m = 1666.7

3 0
3 years ago
Read 2 more answers
Inveres laplace transform (3s-14)/s^2-4s+8​
Olenka [21]

Complete the square in the denominator.

s^2 - 4s + 8 = (s^2 - 4s + 4) + 4 = (s-2)^2 + 4

Rewrite the given transform as

\dfrac{3s-14}{s^2-4s+8} = \dfrac{3(s-2) - 8}{(s-2)^2+4} = 3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}

Now take the inverse transform:

L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}

5 0
2 years ago
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