What is the length of a

What is the answer to this ? PLEASE HELP I HAVE 3 minutes

inn [45]

Answer:

(2, 4)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = 2x

x = -y + 6

Step 2: Solve for y

Substitution

Substitute in x: y = 2(-y + 6)
Distribute 2: y = -2y + 12
Isolate y terms: 3y = 12
Isolate y: y = 4

Step 3: Solve for x

Define equation: x = -y + 6
Substitute in y: x = -4 + 6
Add: x = 2

3 0

3 years ago

Is 6-6 and 1-6 equal

uranmaximum [27]

Answer:

no

Step-by-step explanation:

6-6=0

1-6=-5

7 0

3 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

2 years ago

6x-24 2x+12 Solve for X

Makovka662 [10]

Answer:

x = 9

Step-by-step explanation:

Simplifying

6x + -24 = 2x + 12

Reorder the terms:

-24 + 6x = 2x + 12

Reorder the terms:

-24 + 6x = 12 + 2x

Solving

-24 + 6x = 12 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.

-24 + 6x + -2x = 12 + 2x + -2x

Combine like terms: 6x + -2x = 4x

-24 + 4x = 12 + 2x + -2x

Combine like terms: 2x + -2x = 0

-24 + 4x = 12 + 0

-24 + 4x = 12

Add '24' to each side of the equation.

-24 + 24 + 4x = 12 + 24

Combine like terms: -24 + 24 = 0

0 + 4x = 12 + 24

4x = 12 + 24

Combine like terms: 12 + 24 = 36

4x = 36

Divide each side by '4'.

x = 9

Simplifying

x = 9

4 0

1 year ago

On a manufacturer's assembly line, 3% of its merchandise comes off defective. If the company has 354 defective items, how many t

Rainbow [258]

3% of x = 354 3%∗1100%∗x=3543x100=354Can you solve that for x?

8 0

3 years ago

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