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3 years ago

8

If a graduated cylinder's water level reads 50.0 mL, and you add a rock to it so the water level rises to 54.0 mL, what is the v

olume of the rock?

1 answer:

Ira Lisetskai [31]3 years ago

8 0

The volume of the rock is 4mL

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The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.

enot [183]

Answer:

$\large \boxed{\text{21.6 L}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 180.16

C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g: 24.5

(a) Moles of C₆H₁₂O₆

$\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}$

(b) Moles of CO₂

$\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}$

(c) Volume of CO₂

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37 °C

(i) Convert the temperature to kelvins

T = (37 + 273.15) K= 310.15 K

(ii) Calculate the volume

$\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}$

7 0

3 years ago

In which group of teh modern periodic table are there very reactive metals and very reactive non metals?

Rufina [12.5K]

Metals :-

Group 1A - Alkali metals ( highly reactive metals)

Non-metals :-

Group 17 - Halogens ( highly reactive non-metals )

5 0

4 years ago

While working near a radioactive mine, workers usually wear heavy plastic suits. These suits protect them from all but

Vaselesa [24]

The appropriate response is gamma radiation. Alpha particles can be halted via air. UV radiation can be halted by a typical layer of clothing.Beta particles can be ceased by the thick plastic suit. Just gamma radiation can enter the substantial suit. It must be halted by thick dividers of lead or cement.

4 0

3 years ago

Read 2 more answers

g For the following reaction, 0.500 moles of silver nitrate are mixed with 0.285 moles of copper(II) chloride. What is the formu

scZoUnD [109]

Answer:

$CuCl_2$ is the formula for the limiting reagent.

Mass of silver chloride produced is 71.8 g.

Explanation:

$CuCl_2+2AgNO_3\rightarrow 2AgCl+Cu(NO_3)_2$

Moles of silver nitrate = 0.500 mol

Moles of copper(II) chloride = 0.285 mol

According to reaction, 2 moles of silver nitrate reacts with 1 mole of copper chloride , then 0.500 mole of silver nitrate will react with :

$\frac{1}{2}\times 0.500 mol=0.250 mol$ of copper(II) chloride

As we can see that moles of copper(II) chloride will be reacting is 0.250 mol less than present moles of copper (II) chloride ,so this means that silver nitrate is limiting reagent.

And moles of silver chloride to be formed will depend upon silver nitrate.

According to reaction, 2 moles of silver nitrate gives 2 moles of silver chloride , then 0.500 mole of silver nitrate will give :

$\frac{2}{2}\times 0.500 mol=0.500 mol$ of silver chloride

Mass of silver chloride produced:

0.500 mol × 143.5 g/mol = 71.8 g

7 0

3 years ago

A student is building an electrical circuit. Which material should she choose for wires, and why.

r-ruslan [8.4K]

D. A metal such as copper, because its atom have very mobile electrons - A-p-e-x verified!

<u>Have a Great Day!</u>

3 0

3 years ago