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ExtremeBDS [4]
3 years ago
15

How many electrons are found in a C and O2-, respectively?

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
8 0

Answer:

For example: O2- indicates an ion of oxygen having two extra electrons. I.e., since an oxygen atom normally has 8 protons and 8 electrons, this ion has 10 electrons (-10 charge) and 8 protons (+8 charge) giving it a charge of -2 (-10 + 8 = -2).

You might be interested in
Which diagram above has 4 valence electrons?
Gemiola [76]

Answer:

answer A has four valence electrons

Explanation:

The outer shell has 4 electrons, which are considered the valence electrons

8 0
3 years ago
The density of ethanol is 0.789 g/mL. Calculate the volume of 600 g of ethanol.
Anettt [7]

Answer:

The answer is

<h2>760.46 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of ethanol = 600 g

density = 0.789 g/mL

It's volume is

volume =  \frac{600}{0.789}  \\  = 760.4562737...

We have the final answer as

<h3>760.46 mL</h3>

Hope this helps you

6 0
3 years ago
Which of the following is insoluble in water?
bija089 [108]

Answer:

I think Is A

Explanation:

5 0
3 years ago
La precipitación ácida es un agente de?
serg [7]

Answer:

acid precipitation is an agent of

Explanation:

4 0
3 years ago
3. A student carries out the clay-catalyzed dehydration of cyclohexanol starting with 10 moles of cyclohexanol and obtains 500 m
IrinaK [193]

Answer:

49.45~%

Explanation:

In this case, we have to start with the <u>chemical reaction</u>:

C_6H_1_2O~->~C_6H_1_0~+~H_2O

So, if we start with <u>10 mol of cyclohexanol</u> (C_6H_1_2O) we will obtain 10 mol of cyclohexanol (C_6H_1_0). So, we can calculate the grams of cyclohexanol if we<u> calculate the molar mass:</u>

(6*12)+(10*1)=82~g/mol

With this value we can calculate the grams:

10~mol~C_6H_1_0\frac{82~g~C_6H_1_0}{1~mol~C_6H_1_0}=820~g~C_6H_1_0

Now, we have as a product 500 mL of C_6H_1_0. If we use the <u>density value</u> (0.811 g/mL). We can calculate the grams of product:

500~mL\frac{0.811~g}{1~mL}=405.5~g

Finally, with these values we can calculate the <u>yield</u>:

%~=~\frac{405.5}{820}x100~=~49.45%%= (405.5/820)*100 = 49.45 %

See figure 1

I hope it helps!

6 0
3 years ago
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