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DanielleElmas [232]
2 years ago
8

The combustion reaction of propane is described by the reaction. C3H8 + 5O2 ? 4H2O + 3CO2. How many moles of O2 are required to

generate 3 moles of CO2?
Chemistry
1 answer:
Minchanka [31]2 years ago
7 0

the Answer would be one mole

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Why does a gold isotope, with an atomic number of 79, require more neutrons to be stable than a sodium isotope, with an atomic n
Leya [2.2K]

Here’s a simplified explanation.

The <em>protons</em> in the nucleus <em>repel each other</em>. The <em>neutrons provide the “glue”</em> that holds the nucleus together and prevents it from flying apart.

The “glue” is the strong nuclear force. It is strong but extremely short range. It falls off extremely rapidly as the p-n distance increases.

A <em>neon atom</em> has 10 protons. There are three stable isotopes, with 10, 11, and 12 neutrons.

With fewer than 10 protons, the glue is not strong enough to hold the nucleus together.

If there are more than 12 neutrons, the average p-n distance is great enough that the glue has again become too weak.

<em>Gold</em> has one stable isotope. It contains 79 protons and 118 neutrons.

If there are fewer than 118 neutrons, the proton repulsions will be too strong for the strong force. If there are more than 118 neutrons, the average p-n distance will be large enough that the glue will again be too weak to hold the nucleus toge ther.

8 0
3 years ago
Select the most likely product for this reaction: upper a g upper n upper o subscript 3 (a q) plus upper n a upper o upper h (a
Mamont248 [21]

One of the most likely products for the reaction would be Ag_2O

<h3>Chemical reactions</h3>

The reaction between AgNO_3 and NaOH yields 3 products which are Ag_2O (a precipitate), NaNO_3, and H_2O as shown by the equation below:

2 AgNO_3 + 2 NaOH --- > Ag_2O + 2 NaNO_3 + H_2O

One of the products precipitates out of the solution to give the reaction a precipitation reaction look.

More on precipitation reaction can be found here: brainly.com/question/24158764

#SPJ4

5 0
2 years ago
Read 2 more answers
Suppose that a fictitious element, x, has two isotopes: 59x (59.015 amu) and 62x (62.011 amu). the lighter isotope has an abunda
professor190 [17]

The atomic mass of the element would simply be equal to the sum of the weighted average of each isotope, that is:

atomic mass = 59.015 amu * 0.717 + 62.011 amu * (1 – 0.717)

<span>atomic mass = 59.863 amu</span>

4 0
3 years ago
*multiple choice*
OleMash [197]
I think the answer is A but I could be wrong
4 0
2 years ago
Determine the heat needed to warm 25.3 g of copper from 22 degrees celsius to 39 degrees celsius.
Serggg [28]

Answer:

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed  or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have mass of copper = m = 25.3 g

Specific heat of copper = c = 0.385 J/g°C

ΔT  = 39°C - 22°C = 17°C

Heat absorbed by the copper :

Q=25.3 g\times 0.385 J/g^oC\times 17^oC=165.59 J

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

5 0
3 years ago
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