Energy required to raise the temperature from 35°C - 45 °C= 25116 J.
specific heat, the quantity of warmth required to raise the temperature of one gram of a substance by means of one Celsius degree. The units of precise warmth are generally energy or joules consistent with gram according to Celsius diploma. for instance, the unique warmth of water is 1 calorie (or 4.186 joules) according to gram in step with Celsius degree.
solving,
Sample of liquid = 400. 0 g
temperature = 30. 0 ºc
joules of energy are required to raise the temperature of the water to 45. 0 ºc
therefore rise in temperature 45 - 30 = 15°C
Specific heat capacity = 4.186 J/g m °C
In kelvin = 273 + 15 = 288
= ∴ energy required = Q = m s ( t final - t initial)
= 400*4.186 * 15
= 25116 joule
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Change of state occurs when heat is supplied or removed from a substance.
<h3>What is change of state?</h3>
Change of state refers to the changes that occur when a substance changes from one physical state to another due to changes in its temperature.
It is also known as phase change.
Phase Change can also be defined as change from one state to another without a change in chemical composition.
Some of the phase changes include:
- Freezing: when liquid changes to solid
- Condensation: when gas changes to liquid
- Melting: when solid changes to liquid
- Evaporation: when liquid changes to gas
The other terms associated with phase change include:
- Boiling point: the temperature at which vapor pressure becomes high that causes bubbles to form inside the body of the liquid
- Freezing point: temperature wherein a liquid solidifies
- Melting point: the temperature at which solid turns into a liquid.
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The percentage of atoms in the universe that are hydrogen are 90%
The specific gravity of a sample is the ratio of the density of the sample with respect to one standard sample. The standard sample used in specific gravity calculation is water whose density is 1 g/mL. The solution having specific gravity 1.30 is the density of the sample that is 1.30 g/mL. Thus the weight of the 30 mL sample is (30×1.30) = 39 g.
Now the mass of the 10 mL of water is 10 g as density of water is 10 g/mL. Thus after addition the total mass of the solution is (39 + 10) = 49g and the volume is (30 + 10) = 40 mL. Thus the density of the mixture will be 
g/mL. Thus the specific gravity of the mixed sample will be 1.225 g/mL.
Answer:224
Explanation:
We should answer it with Stoichiometry
We say: 20 g H2× (1 mol/ 2g)× ( 22.4 lit/ 1 mol) = 224
Means: we have 20 grams and every 2g H2, equals to 1 mol of it and every 1 mol of H2, equals to 22.4 lit( because of STP)
hope you got this:)
