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Strike441 [17]
3 years ago
10

Which solution is possible: 7+x <19 x=4 x=12 x=13 x=19 Other:

Mathematics
2 answers:
ZanzabumX [31]3 years ago
8 0

Answer:

none of the above, you need a lesser number

Tamiku [17]3 years ago
4 0

Answer:

x = 4

Step-by-step explanation:

Note that it is only less than, not less than or equal too. Numbers that are 11 & less are the only ones that work.

x = 4 is your only answer choice that is less than 11, therefore is your only answer.

~

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A physical education department wanted a single test of upper body strength that was easy to administer. Dips on the parallel ba
Gennadij [26K]

Answer:

24.23 ; 13.47 ; 0.782 ; p value < 0.00001 ;7.45

Step-by-step explanation:

Given that :

ΣX = 3,416, ΣY = 1,899, SDX = 8.84, SDY = 4.70, ΣZXZY = 109.416

Sample size, N = 141

Mean of X:

£X / N = 3416 / 141 = 24.23

Mean of Y:

£Y / N = 1899 / 141 = 13.47

B.) Correlation between the 2 variables :

£ZXZY / N - 1

= 109.416 / 140

= 0.782

C.)

Level of significance and p value :

T = [Rsqrt(n-2)] ÷ sqrt(1 - R²)

T = [0.782 * sqrt(139)] ÷ sqrt(1-0.782^2)

T = 14.79

P value from Tscore calculator

Df = 141 - 2 = 139 ; α = 0.05

Pvalue = 0.00001

Pvalue < α ; Hence, a significant positive relationship exists.

To obtain regression model :

Slope = £ZXZY / SDX²

m = 109.416 / 8.84^2 = 1. 4

yintercept = meanY - slope*x

yintercept = 13.47 - 1.4*24.3

yintercept = - 20.55

Equation in slope intercept form:

y = mx + c

y = 1.4x - 20.55

For x = 20

y = 1.4(20) - 20.55

y = 7.45

5 0
3 years ago
Solve this algebraic expression.  7-4x+3=x-16-3x<br><br> Please explain.
alexandr402 [8]

7−4x+3=x−16−3x

Simplify

7−4x+3=x−16−3x

7+−4x+3=x+−16+−3x

(−4x)+(7+3)=(x+−3x)+(−16)(Combine Like Terms)

−4x+10=−2x+−16


−4x+10=−2x−16

Add 2x to both sides.

−4x+10+2x=−2x−16+2x

−2x+10=−16

Subtract 10 from both sides.

−2x+10−10=−16−10

−2x=−26

 Divide both sides by -2.

−2x/−2=−26/−2

x=13

5 0
4 years ago
Read 2 more answers
PLEASE HELP!!
erik [133]
2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha

1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}

3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x
8 0
3 years ago
What's the equation of this sequence 4,8,16,32,64,128,256
lions [1.4K]

Answer:

See below

Step-by-step explanation:

Here we have a function a such that a: \mathbb{N}\to \mathbb{R} and a:n  \mapsto a(n) = a_n

The sequence is denoted as $\{a_n\}_{n\in\mathbb{N}}$ such that \mathbb{N} = \{1, 2, 3, ...\}

For this sequence, we would have

\left\{ {2^n\right\}_{n = 2}^8

But sure it seems to follow

\left\{ {2^n\right\}_{n = 2}^\infty

3 0
3 years ago
Read 2 more answers
A company sells confetti in boxes in the shape of a triangular pyramid. Each box contains 240 cubic centimeters of confetti. If
kvv77 [185]

Answer:

Base, 8 cm; height, 4 cm i think

Step-by-step explanation:

5 0
3 years ago
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