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olchik [2.2K]
3 years ago
13

You roll a pair of six-sided number cubes, numbered 1 through 6. What is the probability of rolling two odd numbers? (Enter your

probability as a fraction
Mathematics
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

1/4 or 25%

Step-by-step explanation:

The probability for rolling an odd number is 50% or  \frac{1}{2} because there are 3 odd numbers, (1, 3, 5) and 6 total outcomes (1, 2, 3, 4, 5, 6). \frac{3}{6} =\frac{1}{2}

The probability for rolling two odd numbers in a row is

\frac{1}{2} *\frac{1}{2} =\frac{1}{4}

So, the probability of rolling an odd number twice is 25% or  \frac{1}{4}.

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What's the ? ,need help asap
zaharov [31]

Answer:

6

Step-by-step explanation:

just a guess

9+3+6+7 = 25

5+5+4+9 = 23

6+8+4+? = 24     ? = 6

8 0
3 years ago
A line has a slope of –5 and a y-intercept of (0, 3). What is the equation of the line that is perpendicular to the first line a
neonofarm [45]
Slope-intercept form:
y=mx+b
m=slope
b=y-intercept

Data of the first line:
m=-5
b=y-intercept=3  (y-intercept=it is the value of "y" when x=0)

y=-5x+3

A line perpendicular to the line y=mx+b will have the following slope:
m`=-1/m

Therefore: the line perpendicular to the line y=-5x+3 will have the following slope:
m´=-1/(-5)=1/5

Point-slope form of a line: we need a point (x₀,y₀) and the slope (m):
y-y₀=m(x-x₀)

We know, the slope (m=1/5) and we have a point (3,2) therefore:
y-y₀=m(x-x₀)
y-2=1/5(x-3)     (point-slope form)
y-2=(1/5)x-3/5
y=(1/5)x-3/5+2
y=(1/5)x+7/5    (slope-intercept form)

Answer: the line perpendicular to the first line will be: y=(1/5)x+7/5



3 0
3 years ago
Read 2 more answers
????????????????????
adoni [48]

im not sure if it is right but i got 920 cm2. is that one of ur answers?

3 0
3 years ago
Read 2 more answers
Brainliest if correct
Ivan
The answer is 20x-4, hope this helps.
3 0
3 years ago
The diameters of F and G are 5 and 6 units, respectively. Find each measure.
harkovskaia [24]

Answer:

Part 8) B.F=0.5 units

Part 9) A.B=2 units

Step-by-step explanation:

we have

The diameter of circle F is 5 units

so

The radius of circle F is r.f=5/2=2.5 units

The diameter of circle G is 6 units

so

The radius of circle G is r.g=6/2=3 units

Part 8) Find B.F

we know that

B.F=G.B-F.G

we have

G.B=rg=3 units

FG=rf=2.5 units

substitute the values

B.F=3-2.5=0.5 units

Part 9) Find A.B

we know that

A.B=A.F-B.F

we have

A.F=r.f=2.5 units

B.F=0.5 units

substitute the values

A.B=2.5-0.5=2 units

7 0
3 years ago
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