The average length of a ladybug can range from 0.08 to 0.4 inches.
So two lengths within the given span are 0.1 inch and 0.3 inches.
Answer:
![\displaystyle 10 = ax + bx \rightarrow x = \frac{10}{a + b}](https://tex.z-dn.net/?f=%5Cdisplaystyle%2010%20%3D%20ax%20%2B%20bx%20%5Crightarrow%20x%20%3D%20%5Cfrac%7B10%7D%7Ba%20%2B%20b%7D)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
![\displaystyle 10 = ax + bx](https://tex.z-dn.net/?f=%5Cdisplaystyle%2010%20%3D%20ax%20%2B%20bx)
<u>Step 2: Solve for </u><em><u>x</u></em>
- Factor:
![\displaystyle 10 = ax + bx \rightarrow 10 = x(a + b)](https://tex.z-dn.net/?f=%5Cdisplaystyle%2010%20%3D%20ax%20%2B%20bx%20%5Crightarrow%2010%20%3D%20x%28a%20%2B%20b%29)
- [Division Property of Equality] Divide a + b on both sides:
![\displaystyle 10 = ax + bx \rightarrow x = \frac{10}{a + b}](https://tex.z-dn.net/?f=%5Cdisplaystyle%2010%20%3D%20ax%20%2B%20bx%20%5Crightarrow%20x%20%3D%20%5Cfrac%7B10%7D%7Ba%20%2B%20b%7D)
Answer:
270
Step-by-step explanation:
Because we do not know what the side lengths are, as long as they multiply to 30m^2, it's fine
For this question, let's just say the base is 5, and the height is 6. If we triple 5, we get 15, and if we triple 6, we get 18. 15*18=270
Now what if, the sides are not 5 and 6. Will the area still be the same? Let's find out.
10*3=30 so we can say for this answer, the base is 3, and the height is 10.
10 tripled is 30, and 3 tripled is 9. 30*9=270
So as we look at these 2 answers. we can conclude that the new area, no matter the side lengths, will be 270
Hope this helpes!
Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.
<u>Step-by-step explanation:</u>
As given by the statement in the problem,
Q may be the middle point, which cut the diagonal PA into 2 equal halves.
In rhombus, diagonals meet at right angles.
which means that PQ = QA
x+2 = 3x - 14
Grouping the terms, we will get,
3x -x = 14+ 2
2x = 16
dividing by 2 on both sides, we will get,
x = 16/2 = 8
8+2 = 3(8) - 14 = 10 = PQ or QA
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