<h2>
Answer:</h2>
![P=(19+50x)ft](https://tex.z-dn.net/?f=P%3D%2819%2B50x%29ft)
<h2>
Step-by-step explanation:</h2>
A rectangle is a quadrilateral whose angles are all right angles. In this problem, we have a rectangle whose height
and whose area is
. We don't know the other side of the rectangle, but let's call it
. So the area of a rectangle is:
![A=h.w](https://tex.z-dn.net/?f=A%3Dh.w)
The perimeter is the distance around a shape in two dimensions. For our rectangle, our perimeter is:
![P=2h+2w](https://tex.z-dn.net/?f=P%3D2h%2B2w)
So our goal is to find
. From the equation of the area:
![w=\frac{A}{h} \\ \\ w=\frac{225x}{9}=25x](https://tex.z-dn.net/?f=w%3D%5Cfrac%7BA%7D%7Bh%7D%20%5C%5C%20%5C%5C%20w%3D%5Cfrac%7B225x%7D%7B9%7D%3D25x)
If we substitute both this value and the height in the equation of the perimeter we get:
![P=2(9+25x)ft \\ \\ \boxed{P=(19+50x)ft}](https://tex.z-dn.net/?f=P%3D2%289%2B25x%29ft%20%5C%5C%20%5C%5C%20%5Cboxed%7BP%3D%2819%2B50x%29ft%7D)
Answer:
a = 4
Step-by-step explanation:
![\sin(theta) = \frac{opposite}{hypotenuse}](https://tex.z-dn.net/?f=%20%5Csin%28theta%29%20%20%3D%20%20%5Cfrac%7Bopposite%7D%7Bhypotenuse%7D%20)
![\cos(theta) = \frac{adjacent}{hypotenuse}](https://tex.z-dn.net/?f=%20%5Ccos%28theta%29%20%20%3D%20%20%5Cfrac%7Badjacent%7D%7Bhypotenuse%7D%20)
![\tan(theta) = \frac{opposite}{adjacent}](https://tex.z-dn.net/?f=%20%5Ctan%28theta%29%20%20%3D%20%20%5Cfrac%7Bopposite%7D%7Badjacent%7D%20)
hypotenuse = a
opposite = 2√3
adjacent = b
theta = 60°
the best formula to use is the first formula cause we have all the values to substitute in it in order to find the value of a
![\sin(60) = \frac{2 \sqrt{3} }{a}](https://tex.z-dn.net/?f=%20%5Csin%2860%29%20%20%3D%20%20%5Cfrac%7B2%20%5Csqrt%7B3%7D%20%7D%7Ba%7D%20)
![\frac{2 \sqrt{3} }{ \sin(60) } = a](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%20%5Csqrt%7B3%7D%20%7D%7B%20%5Csin%2860%29%20%7D%20%20%3D%20a)
![4 = a](https://tex.z-dn.net/?f=4%20%3D%20a)
![a = 4](https://tex.z-dn.net/?f=a%20%3D%204)
Answer:
Step-by-step explanation:
perimeter =76 m
L=3+w
w
2L+2W=76
2(3+W)+2W=76
6+2w+2w=76
4w=70
w=70/4
w=17.50
L=17.50+3=20.50
A=L*W=17.50*20.50=358.75m^2
Answer:
C. geometric; 125
Step-by-step explanation:
first term(a) = 0.2
common ratio (r) = 1 / 0.2 = 5
now
Tn = ar^ n -1
t5 = 0.2 * 5^ 4
= 125
hope it helps :)
Hello thank you for the free points :3