<span>Simplifying
(6a + -8b)(6a + 8b) = 0
Multiply (6a + -8b) * (6a + 8b)
(6a * (6a + 8b) + -8b * (6a + 8b)) = 0
((6a * 6a + 8b * 6a) + -8b * (6a + 8b)) = 0
Reorder the terms:
((48ab + 36a2) + -8b * (6a + 8b)) = 0
((48ab + 36a2) + -8b * (6a + 8b)) = 0
(48ab + 36a2 + (6a * -8b + 8b * -8b)) = 0
(48ab + 36a2 + (-48ab + -64b2)) = 0
Reorder the terms:
(48ab + -48ab + 36a2 + -64b2) = 0
Combine like terms: 48ab + -48ab = 0
(0 + 36a2 + -64b2) = 0
(36a2 + -64b2) = 0
Solving
36a2 + -64b2 = 0
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right.
Add '64b2' to each side of the equation.
36a2 + -64b2 + 64b2 = 0 + 64b2
Combine like terms: -64b2 + 64b2 = 0
36a2 + 0 = 0 + 64b2
36a2 = 0 + 64b2
Remove the zero:
36a2 = 64b2
Divide each side by '36'.
a2 = 1.777777778b2
Simplifying
a2 = 1.777777778b2
Take the square root of each side:
a = {-1.333333333b, 1.333333333b}</span>
Answer:
it will 16y-8x and common 8 is so 2y-x
Answer:
2 / z - 9
Step-by-step explanation:
Don't worry division always goes before subtraction so you don't need any parenthesis.
Tell me if I'm wrong :)
Depending on the values of 'r', 't', and 'e', the numerical value of that expression
might have many factors.
For example, if it happens that r=5, t=1, and e=4 for an instant, then, just
for a moment, (r + t)(e) = (5+1)(4) = 24, and the factors of (r+t)(e) are
1, 2, 3, 4, 6, 8, 12, and 24 . But that's only a temporary situation.
The only factors of (r+t)(e) that don't depend on the values of 'r', 't', or 'e' ,
and are always good, are (<em>r + t</em>) and (<em>e</em>) .
Answer:
hi
Step-by-step explanation:
