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kipiarov [429]
3 years ago
7

The parabola is swached vertically by a factor of 5.

Mathematics
1 answer:
kobusy [5.1K]3 years ago
5 0

Answer:

answer below

Step-by-step explanation:

I think you mean "squashed" or "stretched" vertically by a factor of 5.

f(x) is the original parabola equation

g(x) = 5f(x) is vertically stretched by a factor of 5

(x,y) -> (x , 5y)

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A factory makes rectangular sheets of cardboard, each with an area of 2 1 2square feet. Each sheet of cardboard can be cut into
hodyreva [135]

Answer:

2 1/7 pieces

Step-by-step explanation:

A factory makes rectangular sheets of cardboard, each with an area 2 1/2 square feet. Each sheet of cardboard can be cut into smaller pieces of cardboard measuring 1 1/6 square feet. How many smaller pieces of cardboard does each sheet of cardboard provide?

Each sheet of cardboard = 2 1/2 square feet

Each smaller pieces of cardboard = 1 1/6 square feet

Number of smaller pieces of cardboard per sheet of cardboard = Each sheet of cardboard ÷

Each smaller pieces of cardboard

= 2 1/2 square feet ÷ 1 1/6 square feet

= 5/2 ÷ 7/6

= 5/2 × 6/7

= (5*6) / (2*7)

= 30/14

= 15/7

= 2 1/7 pieces

Number of smaller pieces of cardboard per sheet of cardboard = 2 1/7 pieces

6 0
3 years ago
Help! I need the answers quick please
Norma-Jean [14]

Answer:

No idea

Step-by-step explanation:

8 0
3 years ago
When sending a rectangular package through the U.S. Postal Service, the combined length and girth (perimeter of the cross sectio
weqwewe [10]
Let W = width of package
Let H = height of package
Let L = length of package

The perimeter cab be one of the following:
P = 2(L + W),  or
P = 2(L + H)

The perimeter of the cross section cannot exceed 108 in.
When the width is 10 in, then
 2(L + 10) <= 108
 L + 10 <= 54
 L <= 44 in

When the height is 15 in, then
2(L + 15) <= 108
L + 15 <= 54
L <= 39 in

To satisfy both of these conditions requires that L <= 39 in.

Answer: 39 inches
5 0
3 years ago
B
Tomtit [17]
This would be 525 / 0.70  = $750 Answer
8 0
3 years ago
A conical container can hold 120π cubic centimeters of water. The diameter of the base of the container is 12 centimeters.
Tanzania [10]

Answer: The height of the container is 10 centimeters. If its diameter and height were both doubled, the container's capacity would be 8 times its original capacity.

Step-by-step explanation:

The volume of a cone can be calculated with this formula:

V=\frac{\pi r^2h}{3}

Where "r" is the radius and "h" is the height.

We know that the radius is half the diameter. Then:

r=\frac{12cm}{2}=6cm

We know the volume and the radius of the conical container, then we can find "h":

120\pi cm^3=\frac{\pi (6cm)^2h}{3}\\\\(3)(120\pi cm^3)=\pi (6cm)^2h\\\\h=\frac{3(120\pi cm^3)}{\pi (6cm)^2}\\\\h=10cm

The diameter and height doubled are:

d=12cm*2=24cm\\h=10cm*2=20cm

Now the radius is:

r=\frac{24cm}{2}=12cm

And the container capacity is

V=\frac{\pi (12cm)^2(20cm)}{3}=960\pi cm^3

Then, to compare the capacities, we can divide this new capacity by the original:

 \frac{960\pi cm^3}{120\pi cm^3}=8

Therefore,  the container's capacity would be 8 times its original capacity.

6 0
3 years ago
Read 2 more answers
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