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Korvikt [17]
3 years ago
12

The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive

rsities. Suppose we take a poll (random sample) of 3957 students classified as Juniors and find that 3226 of them believe that they will find a job immediately after graduation. What is the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation?
Mathematics
1 answer:
sergejj [24]3 years ago
7 0

Answer:

Step-by-step explanation:

Using the formula

p +/- z* √(p(1-p) / n)

Where p is sample proportion = 3226/3957 = 0.8153, n = 3957 and z* is 2.576

0.8153 + (2.576 √(0.8153(1-0.8153) / 3957))

0.8153 + (2.576 √ (0.8153(0.1847) /3957)

0.8513 + (2.576 √(0.1572/3957)

0.8513 + (2.576 √0.00003974)

0.8513 + 2.576(0.0063)

0.8513 + 0.016

0.8670 ~ 87%

For the lower interview

0.8513 - 0.016

= 0.8353 ~ 84%

Thus, at 99% confidence interval is 84% and 87%

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Convert 9.3 kribs into grees given that 4.2 kribs = 18 grees.
maria [59]

Answer:

39.9 grees

Step-by-step explanation:

Since 4.2 kribs = 18 grees

Then,

1 krib = 18/4.2 grees

9.3 kribs = (18/4.2) x 9 3

9.3 kribs = 39.9 grees.

4 0
3 years ago
2/5(d−10)−23(d+6)25(d−10)−23(d+6) is 
Dimas [21]
Simplify \frac{2}{5} (d - 10) to \frac{2(d - 10)}{5} :
\frac{2(d - 10)}{5} [/tex] - 23(d + 6) x 25(d - 10) - 23(d + 6)

Simplify 23(d + 6) x 25(d - 10) to 575(d + 6)(d - 10) :
\frac{2(d - 10)}{5} [/tex] - 575(d + 6)(d - 10) - 23(d + 6)

Then Expand : 
\frac{2(d - 10)}{5} [/tex] - 575d^{2} + 5750d - 3450d + 34500 - 23d - 138

Now Collect Like Terms :
\frac{2(d - 10)}{5} [/tex] - 575d^{2} + (5750d - 3450d + 34500 - 23d) + (34500 - 138)

Answer :
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7 0
3 years ago
What is the best approximation of the length of segment QS? (Note: cos 80° = 0.17)
matrenka [14]

Answer: QS=11.8cm


Step-by-step explanation:

1. You have the following information:

- The lenght of RS is 2 centimeters.

- The angle m∠S=80°.

- Cos80°=0.17

2. Therefore, you can calculate the lenght of the segment QS as following:

cos80=\frac{adjacent}{hypotenuse}

adjacent=2cm\\hypotenuse=QS\\cos80=0.17

3. Substitute values and solve for QS:

0.17=\frac{2cm}{QS}\\QS=\frac{2cm}{0.17} \\QS=11.76cm

4. To the nearest tenth:

QS=11.8cm

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3 years ago
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Kobotan [32]

Answer:15,680

Step-by-step explanation:

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Dividing both sides by 0.49, we have

P=7,683.200.49=15,680

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3 years ago
1. The alphabet which can assume<br> different values is called: *
Sedaia [141]

Answer:

variable

Step-by-step explanation:

8 0
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