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stira [4]
2 years ago
11

Find the surface area of the pyramid. The side lengths of the base are equal.

Mathematics
2 answers:
3241004551 [841]2 years ago
5 0

Answer:

er32

tyhg

Step-by-step explanation:

5you

try

try

it

t4

we

kati45 [8]2 years ago
3 0

Answer:

The answer is 172.8 square yards

Step-by-step explanation:

Hope this helped you.

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The function f(x)=x^2 is graphed on the coordinate grid.
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<h3>Answer:</h3>
  • graphed below.
<h3>Explanation:</h3>
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other points:

<u>x    y</u>

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Geometry math question please help
Triss [41]

A square is a figure with four equal sides and four right angles.In a square the diagonals bisect at right angles .

In the above given options option A is the right answer.

If the diagonals of any parallelogram are perpendicular then the figure is not necessarily a square.

Diagonals are perpendicular in a rhombus too.

A square and Rhombus both have diagonals that are perpendicular.

So it is not a necessary condition for a parallelogram to be a square .

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Answer please.. I need help
allsm [11]
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When you set the denominators of 2 / 5 and 1 / 3, equal to each other, you receive a denominator of 15, the only denominator the two have in common
6 0
3 years ago
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
3 years ago
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