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3 years ago

What is the y-intercept of the function described by the data in the table below? Xy -1 5 2 -7 5 -19

Mathematics

1 answer:

marysya [2.9K]3 years ago

8 0

Answer:

Step-by-step explanation:because

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Help please . thank you

S_A_V [24]

PLEASE DONT USE THAT LINK

5 0

3 years ago

How would i answer this?

Paraphin [41]

Answer:

Option (B).

Step-by-step explanation:

Option (a). {(1, 2), (3, 4), (4, 5), (6, 7)}

Since in every ordered pair value of x corresponds a distinct value of y.

The given ordered pairs represent one-to-one function.

Option (b). {(0, 3), (1, 5), (3, 9), (1, 13)}

In the ordered pairs (1, 5) and (1, 13) value of x correspond to the two different values of y.

Therefore, its not a function.

Option (c). {(-2, 2), (-3, 3), (-4, -4), (-5, -5)}

For every value of x there is distinct value of y.

Therefore, given set of ordered pairs represent a one to one function.

Option (d). {(1, 2), (2, 2), (3, 5), (4, 8)}

Ordered pairs represent a function.

Option (B), will be the answer.

3 0

4 years ago

A gym membership costs $25 to join and $14 each month. Write and use an algebraic expression to find the cost of the gym members

lina2011 [118]

Answer:

See below.

Step-by-step explanation:

So we know that a gym membership costs $25 plus $14 each month.

In other words, the one-time cost is $25 and there will be a cost of $14 each month.

We can write this as:

$f(x)=14x+25$

Where f(x) equals the total cost given the number of months x.

For 6 months, the total cost will be:

$f(6)=14(6)+25\\f(6)=84+25\\f(6)=\$ 109$

6 0

4 years ago

A particle is moving with the given acceleration function and initial conditions. Find the velocity function and the position fu

Lerok [7]

Answer:

The velocity function is the particle is $v(t)=-2\cos (t)-4\sin (t)-1$ .

Step-by-step explanation:

The acceleration function of a moving particle is

$a(t)=2\sin (t)-4\cos (t)$

The initial conditions are v(0) = −3, s(0) = 5.

Integrate the acceleration function with respect to time to find the velocity function.

$\int a(t)=\int (2\sin (t)-4\cos (t))dt$

$v(t)=-2\cos (t)-4\sin (t)+C_1$

Use the initial condition v(0) = −3 to find the value of C₁.

$-3=-2\cos (0)-4\sin (0)+C_1$

$-3=-2(1)-4(0)+C_1$

$-3=-2+C_1$

$-3+2=C_1$

$-1=C_1$

So the velocity function is the particle is

$v(t)=-2\cos (t)-4\sin (t)-1$

Integrate the acceleration function with respect to time to find the position function.

$\int v(t)=\int (-2\cos (t)-4\sin (t)-1)dt$

$s(t)=-2\sin (t)+4\cos (t)-t+C_2$

Use the initial condition s(0) = 5 to find the value of C₂.

$5=-2\sin (0)+4\cos (0)-(0)+C_2$

$5=-2(0)+4(1)+C_2$

$5=4+C_2$

$1=C_2$

So, the position function is the particle is $s(t)=-2\sin (t)+4\cos (t)-t+1$ .

5 0

3 years ago

Find the value of the parallelogram

ruslelena [56]

Answer:

x=30

y=22.5

Step-by-step explanation:

each of the corners are 90

3x=90

divide each side by 3

x=30

4y=90

divide each side by 4

x=22.5

5 0

3 years ago