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joja [24]
3 years ago
15

20.   The sum of two consecutive even integers is 158. Find the least of the two integers. 

Mathematics
2 answers:
Aloiza [94]3 years ago
7 0

Answer:

2A + (2A +2)  = 158

4A = 156

A= 39

2A = 78 and (2A + 2) = 80

Answer is A

Step-by-step explanation:

Mumz [18]3 years ago
6 0

Answer:

78

Step-by-step explanation:

The tricky part of this is figuring out how to assign the unknowns.  We are told that we are working with two consecutive even integers.  Consecutive means "next to" or "in order" and sum means to add.  If we use 2 and 4 as examples of our 2 consecutive even integers and assign x to 2, then in order to get from 2 to 4 we have to add 2.  So the lesser of the 2 integers is x, and the next one in order will be x + 2.  (2 and 4 are just used as examples; they mean nothing to the solving of this particular problem.  You could pick any 2 even consecutive integers and find the same rule applies.  All we are doing here with the example numbers is finding a rule for our integers.)  Now we have the 2 expressions for the integers, we will add them together and set the sum equal to 158:

x + (x + 2) = 158

The parenthesis are unnecessary since we are adding, so when we combine like terms we get

2x + 2 = 158 and

2x = 156 and

x = 78

That means that the lesser of the 2 integers in 78, and the next one in order would be 80, and 78 + 80 = 158

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Step-by-step explanation:

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56. CHALLENGE Let and be two distinct rational numbers. Find the
Katen [24]

The rational number that lies exactly halfway between a/b and c/d on a number line is x = (ad + bc)/2bd or 1/2(a/b + c/d).

<h3>How to calculate the mid-value?</h3>

To calculate the mid-value of two numbers x and y, find the average of these two numbers. I.e., (x + y)/2

Thus, the average of these two numbers is the mid-value between them.

<h3>Calculation:</h3>

It is given that,

a/b and c/d are the two rational numbers on a number line.

Consider the required rational number that lies exactly halfway between a/b and c/d as 'x'.

Then, the mid-value of these two rational numbers is

(a/b + c/d)/2

⇒ (ad + bc)/2bd  ...(i)

To know that the obtained rational number is exactly halfway between a/b and c/d, consider the distance from a/b to x and c/d to x.

So, the distance from a/b to x is - "x - a/b" (x > a/b) and

the distance from x to c/d is - "c/d - x"

From the given condition, the above-obtained distances are equal

⇒ x - a/b = c/d - x

⇒ x + x = a/b + c/d

⇒ 2x = (ad + bc)/bd

⇒ x = (ad + bc)/2bd ...(ii)

From (i) and (ii), it is concluded that the required rational number is

x = (ad + bc)/2bd

Learn more about finding mid-value between two rational numbers here:

brainly.com/question/5556240

#SPJ9

Disclaimer: The given question on the portal was incomplete. Here is the complete question.

Question: CHALLENGE: Let a/b and c/d be two distinct rational numbers. Find the rational number that lies exactly halfway between a/b and c/d on a number line.

8 0
2 years ago
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