Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Answer:
True ( A )
Step-by-step explanation:
4 ( 5 ) - 2 = 2 ( 5 ) + 8
20 - 2 = 10 + 8
18 = 18
This is a correct statement because 18 does equal 18
Answer: 100
Hi!
ok so the Pythagorean theorem is
so the other side is 10.
the square 8 is 8*8
and square 6 is 6*6
so the other square is 10*10=100.
so the area of the blank square is 100.
Step-by-step explanation:
Can I have brainliest?
Thanks!
Have a nice day!
T=0 is also a solution. Other than 0 here is a solution.
