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agasfer [191]
4 years ago
5

50 POINTS IF YOU ANSWER THE FOLLOWING QUESTION PLEASE https://brainly.com/question/15324380

Mathematics
2 answers:
Jet001 [13]4 years ago
7 0

Answer:

I added an answer. It was -2x^4

Step-by-step explanation:

Grace [21]4 years ago
3 0

Answer:

I answered it :)  Look at the link.

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Y=2x+6 <br> 3y-x+3=0 <br><br> Substitute to solve <br><br> Brainliest for correct answer
wel

Answer:

-21/5 or -4.2

Step-by-step explanation:

y = 2x + 6

3y - x + 3 = 0

Substitute the value for y from the first equation into the second equation.  Solve for x.

3y - x + 3 = 0

3(2x + 6) - x  + 3= 0

6x + 18 - x + 3 = 0

5x + 18 + 3 = 0

5x + 21 = 0

5x + 21 - 21 = 0 - 21

5x = -21

x = -21/5 or -4.2

3 0
3 years ago
darcy,Jason n maria share $268. Jason has $20 more than darcy n maria has twice as much money as Jason. how much money do darcy
jok3333 [9.3K]
X is how much Darcy has because she has the least. (x+20) is how much Jason has and 2(x+20) is how much Maria has.
x+(x+20)+2(x+20)=268
4x+60=268
4x=208
x= $52

Darcy has $52
Jason has $72
Maria has $144
6 0
3 years ago
Answer it plz! Thx!!!!
Softa [21]
An icy body that releases gas or dust with a tail thats always pointed away from the sun

5 0
3 years ago
Read 2 more answers
If x:5 = 18:30,then x =​
iris [78.8K]

Answer:

3

Step-by-step explanation:

                                                                                x:5 = 18:30

Convert to the least common denominator     6x:30 = 18 :30

Divide each side by 6                                             6x = 18

                                                                                  x =   3  

3 0
3 years ago
Determine the domain and range Express your answer in interval notation
Dmitriy789 [7]

The domain of a function is the set of all values that the x-variable can take.

On the other hand, the range of the function is the set of all values that the function takes when it is evaluated at elements of the domain.

For the given expression:

p(x)=-\frac{1}{(x-1)^2}

The denominator is (x-1)^2. Since the denominator must be different from 0, then:

\begin{gathered} (x-1)^2\ne0 \\ \Rightarrow x-1\ne0 \\ \Rightarrow x\ne1 \end{gathered}

Then, the only restriction for the variable x is not to be equal to 1. Then, the domain of p(x) is the set of all real numbers except 1, which can be written using interval notation as:

(-\infty,1)\cup(1,\infty)

Since the exponent of the denominator is 2, then the denominator is always positive. Since the coefficient of the term 1/(x-1)^2 is -1, then the whole expression must always be negative. Additionally, there is no way in which the expression can be equal to 0.

Then, the range of the function is the set of all negative numbers, which can be expressed using interval notation as:

(-\infty,0)

Therefore, the answers are:

\begin{gathered} \text{ Domain: }(-\infty,1)\cup(1,\infty) \\  \\ \text{ Range: }(-\infty,0) \end{gathered}

7 0
1 year ago
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