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faltersainse [42]
3 years ago
6

Could anyone please help?​

Mathematics
2 answers:
Stells [14]3 years ago
5 0

Answer:

MN = b - a

Step-by-step explanation:

N = \frac{1}{2}BA

BA = a - b = 4a - 2b

\frac{1}{2}BA = \frac{1}{2} (4a - 2b) = 2a - b

Thus

MN = MO + OB + \frac{1}{2} BA

      = - 3a + 2b + 2a - b

     = b - a

natima [27]3 years ago
3 0

Answer:

b+3a

Step-by-step explanation:

MN=AN+AM

AN=0.5*AB

AB=OA+OB=4a+2b

AN=2a+b

AM=OA-OM=4a-3a=a

MN=2a+b+a=3a+b

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quester [9]
Hi! 

To compare this two sets of data, you need to use a t-student test:

You have the following data:

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You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

t= \frac{X1-X2}{ \sqrt{ \frac{(n1-1)* s1^{2}+(n2-1)* s2^{2} }{n1+n2-2}} * \sqrt{ \frac{1}{n1}+ \frac{1}{n2}} } =2,2510

To calculate the degrees of freedom you need to use the following equation:

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The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10

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3 years ago
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3 years ago
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Vladimir79 [104]
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