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Rina8888 [55]
2 years ago
12

In an effort to prepare for retirement, Zeus decided to sell off some of his powers to Poseidon. Each box of powers contained 4

specific powers. Each box cost Zeus $250. If Zeus wanted to make a profit $900 per box, how much would have to charge Poseidon for each power?
Mathematics
1 answer:
USPshnik [31]2 years ago
4 0

Answer:

<h2>  $287.50</h2>

Step-by-step explanation:

From the problem statement the cost price per box is

$250.

And the box contains 4 specific powers, since Zeus plans to make $900 per box  which contains 4 powers

we need to find the selling price

profit= selling price-cost price

let the selling price be x

900=x- 250

x=900+250

x= 1150

Selling price = $1150

<em>Hence the unit cost of a specific power in a box that will see a profit of $900 per box is 1150/4= $287.50</em>

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Find the dimensions of a rectangle with perimeter 116 m whose area is as large as possible. (if both values are the same number,
creativ13 [48]
The dimensions would be 29 by 29.

To maximize area and minimize perimeter, we make the dimensions as close to equilateral as possible.  

Dividing the perimeter by the number of sides, we have

116/4 = 29

This means that both length and width can be 29.
5 0
3 years ago
Which of the following is the balance for a single $3,200 deposit in an account with an APR of 2.6% that compounds interest quar
Flauer [41]

Answer:

FV= 3200(1+\frac{0.026}{3})^{3(6)}=3200 (1.008667)^{54}= 50994.590

Step-by-step explanation:

For this case we can use the formula for the future value with compound interest given by:

FV= P (1+\frac{r}{n})^{nt}   (1)

For this case since the interest is compounded quarterly we have 3 periods each year, since we have 3 quarters in a year.

r represent the rate =0.026

t = 6 represent the number of years

P = 3200 represent the amount invested at the begin

If we apply the formula (1) we got:

FV= 3200(1+\frac{0.026}{3})^{3(6)}=3200 (1.008667)^{54}= 50994.590

So then the balance after 6 years would be approximately 50995 with the conditions provided.

7 0
2 years ago
15.624 as a fraction
Fittoniya [83]

15 624/1000   is it supposed to be sipplified?

8 0
2 years ago
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Answer:

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7 0
3 years ago
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In a previous​ year, 51​% of females aged 15 and older lived alone. A sociologist tests whether this percentage is different tod
Yanka [14]

Answer:

Given:

n = 550

Po = 51% = 0.51

P0 - 1 = 0.51 - 1 = 0.49

p' = \frac{287}{550} = 0.5218

np0(1 - p0) = 550*0.51(1-0.51)

= 137.4 ≥ 100

This means the sample size is greater than 5% of the population size. and the sample can be reasonably assumed to be random, the requirement for testing hypothesis are satisfied.

1) The null and alternative hypotheses:

H0 : p0 = 0.51

H1 : p0 ≠ 0.51

The test statistic Z,

Z = \frac{p' - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}

Z = \frac{0.5218 - 0.51}{\sqrt{\frac{0.51(1-0.51)}{550}}}

Z = 0.55

This is two tailed test.

The pvalue for Z =0.55

Pvalue = 0.5824

3) Decision:

Since pvalue, 0.5824 is greater than significance level, we fail to reject null hypothesis H0.

Conclusion:

Do not reject Upper H0. There is not sufficient evidence at the alpha equals 0.01 level of significance to conclude that the proportion of females who are living alone has changed.

8 0
3 years ago
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