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3 years ago

Determine the perimeter of a equilateral triangle with the sides of 28 cm.

Mathematics

1 answer:

Arada [10]3 years ago

3 0

Answer:

Step-by-step explanation:

28*3

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Write the log equation as an exponential equation. You do not need to solve for x.

V125BC [204]

Answer:

(x-6)^3x-5 =6

Step-by-step explanation:

logb a=c ------> b^c =a

7 0

3 years ago

Which of the following is the equation for the graph shown?a. x^2/144+y^2/95=1b. x^2/144-y^2/95=1c. x^2/95+y^2/144=1d. x^2/95-y^

Andrews [41]

e follSOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the general equation of an ellipse

$\frac{\mleft(x-h\mright)^2}{a^2}+\frac{(y-h)^2}{b^2^{}}=1$

STEP 2: Identify the parameters

the length of the major axis is 2a

the length of the minor axis is 2b

$\begin{gathered} 2a=24,a=\frac{24}{2}=12 \\ 2b=20,b=\frac{20}{2}=10 \end{gathered}$

STEP 3: Get the equation of the ellipse

$\begin{gathered} By\text{ substitution,} \\ \frac{(x-h)^2}{a^2}+\frac{(y-h)^2}{b^2}=1 \\ \frac{(x-0)^2}{12^2}+\frac{(y-0)^2}{10^2}=1=\frac{x^2}{144}+\frac{y^2}{100}=1 \end{gathered}$

STEP 4: Pick the nearest equation from the options,

Hence, the equation of the ellipse in the image is given as:

$\frac{x^2}{144}+\frac{y^2}{95}=1$

OPTION A

8 0

1 year ago

Please i suck at math lol 2.0

Salsk061 [2.6K]

Answer:

i- ;-;

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Multi-step K is the midpoint of JL, JL=4x-2, and JK=7. Find x, KL, and JL

ddd [48]

If K is midpoint of JL then JK = 0.5JL

JL = 4x - 2; JK = 7

The equation:
0.5(4x - 2) = 7
2x - 1 = 7 |add 1 to both sides
2x = 8 |divide both sides by 2
x = 4

JL = 4(4) - 2 = 16 - 2 = 14

KL = JK = 7

7 0

3 years ago

Factor the following expression. Simplify your answer. 3s(s - 1)^1/3 + 2(s - 1)^4/3

denis23 [38]

Answer:

Step-by-step explanation:

$3s\sqrt[3]{s-1} + 2 \sqrt[4/3]{s-1} =\\3s\sqrt[3]{s-1} + 2 \sqrt[1/3]{(s-1)^4} =\\3s\sqrt[3]{s-1} + 2 (s-1)\sqrt[1/3]{s-1} =\\\sqrt[3]{s-1}*(3s + 2 (s-1)) =\\\sqrt[3]{s-1}*(3s + 2s-2)) =\\\sqrt[3]{s-1}*(5s -2) \\$

6 0

2 years ago

Read 2 more answers