Answer:
(300*80) + (300*9) + (20*80) + (20*9) + (5*80) + (5*9) = 28925
Step-by-step explanation:
Given;
325 x 89
Expand 325 = 300 + 20 + 5
Expend 89.0 = 80 + 9
now multiple to two expanded numbers;
(300 + 20 + 5) x (80 + 9)
distribute the number accordingly as follows;
(300*80) + (300*9) + (20*80) + (20*9) + (5*80) + (5*9), now we have Six multiplication problems.
= 24,000 + 2700 + 1600 + 180 + 400 + 45
= 28925
Given A={1,2,3}, B={2,4,6} and C={1,2,3,4,5,6}, then A ∩ (B ∩ C) =
oksian1 [2.3K]
Answer:
Step-by-step explanation:
A={1,2,3}
B={2,4,6}
C={1,2,3,4,5,6}
B∩C={2,4,6}
A∩(B∩C)={1,2,3}∩{2,4,6}={2}
The total length of the segment AC is the sum of AB and CB, which gives, CB = 9
<h3>How can the length of CB be found?</h3>
The given parameters are;
- AC = 17
- AB = 32 + 3•x
- CB = 57 + 6•x
Required: <em>CB</em>
Solution:
AC = <em>AB + CB</em> by segment addition property
Therefore;
AC = 17 = 32 + 3•x + 57 + 6•x = 89 + 9•x
17 = 89 + 9•x
CB = 57 + 6•x = 57 + 6 × (-8) = 9
Therefore;
Learn more about segment addition postulate here: brainly.com/question/1721582
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Answer:
Step-by-step explanation:
4y - 2(5 - y + 4) = 4y - 2(9 - y)
= 4y + 9*(-2) - y *(-2)
= 4y - 18 + 2y {Combine like terms 4y and 2y}
= 6y - 18
6y - 18 = 6*y - 6*3
= 6(y - 3)
6y- 18 = 2 *3y - 2*9
= 2(3y -9)
2(3y - 9) and 6(y- 3 ) are equivalent to 4y - 2(5- y +4)
Others are not equivalent
