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Roman55 [17]
3 years ago
9

What is the slope of a line perpendicular to the line whose equation is 3x-9y=216. Fully reduce your answer.

Mathematics
2 answers:
emmainna [20.7K]3 years ago
5 0
-9y=-3x+216
y=1/3x-24
m=-3
y=-3x+16 is perpendicular to the line
dusya [7]3 years ago
3 0
First, convert it to slope intercept form. That would make it: 

y= \frac{1}{3} x-24

Then, change the slope by finding its negative reciprocal, since it is perpendicular

y= -3x-24
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3 Which of the following represents a function? A {(-2, 1), (-2, 0), (-2, 1), (-2, 2)} B {(-1,0), (0, 1), (1, 2), (2, 3)} C {(1,
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Read 2 more answers
Which classification describes AMNO with vertices M(2, -3), N(3, 1), and<br> 0(-3, 1)?
Sonja [21]

Answer:

Option D

Step-by-step explanation:

32). Given vertices of the triangle are M(2, -3), N(3, 1) and O(-3. 1).

Distance between two points (x_1,y_1) and (x_2,y_2) is given by the expression,

Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between M(2, -3) and N(3, 1) will be,

MN = \sqrt{(3-2)^2+(1+3)^2}

      = \sqrt{1+16}

      = \sqrt{17}

Distance between M(2, -3) and O(-3, 1),

MO = \sqrt{(2+3)^2+(-3-1)^2}

      = \sqrt{25+16}

      = \sqrt{41}

Distance between N(3, 1) and O(-3, 1),

NO = \sqrt{(3+3)^2+(1-1)^2}

      = 6

Condition for right triangle,

c² = a² + b² [Here c is the longest side of the triangle]

By this property,

MO² = MN² + NO²

(\sqrt{41})^2=(\sqrt{17})^2+6^2

41 = 17 + 36

41 = 51

False.

Therefore, given triangle is not a right triangle.

Since, length of all sides are not equal, given triangle will be a scalene triangle.

Option D is the correct option.

5 0
3 years ago
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