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Vaselesa [24]
3 years ago
11

Hey brainless riddle me this

Mathematics
2 answers:
kompoz [17]3 years ago
8 0
What’s the riddle and I bet that I can
Ann [662]3 years ago
5 0
I’m brainless i don’t know any riddles
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I need with this. Someone help please.
seraphim [82]

Answer:

In the ATTACHMENT

Step-by-step explanation:

For the first one, you can plug in multiple numbers of any kind for x and start to form you line.

For the second one, know that the y line is always horizontal. Find -3 on the plot that would be on the y-axis and put that horizontal line on it.

<em>Hope this helps!!</em>

4 0
4 years ago
Please help me <br><br>Marking brainliest for smart answer
Effectus [21]

Answer:

58%

Step-by-step explanation:

47/81 x 100%

≈ 58%

Hope it helps : )

4 0
2 years ago
BRO PLEASE HELP ASAP
KiRa [710]

Answer:

bro i think its 10

Step-by-step explanation:

3 0
3 years ago
What are the solutions of the quadratic equation (x + 3)2 = 49
Korvikt [17]

the right answer is

x = 4 and x = –10

I just take the test and I got it right I hope yall get it right to


8 0
3 years ago
Read 2 more answers
The number of bacteria in a refrigerated food product is given by N ( T ) = 22 T 2 − 123 T + 40 , 6 &lt; T &lt; 36 , where T is
antoniya [11.8K]

Answer:

N(T(t)) = 1408t^2 - 385.6t - 105.52

Time for bacteria count reaching 8019: t = 2.543 hours

Step-by-step explanation:

To find the composite function N(T(t)), we just need to use the value of T(t) for each T in the function N(T). So we have that:

N(T(t)) = 22 * (8t + 1.7)^2  - 123 * (8t + 1.7) + 40

N(T(t)) = 22 * (64t^2 + 27.2t + 2.89) - 984t - 209.1 + 40

N(T(t)) = 1408t^2 + 598.4t + 63.58 -  984t - 169.1

N(T(t)) = 1408t^2 - 385.6t - 105.52

Now, to find the time when the bacteria count reaches 8019, we just need to use N(T(t)) = 8019 and then find the value of t:

8019 = 1408t^2 - 385.6t - 105.52

1408t^2 - 385.6t - 8124.52 = 0

Solving this quadratic equation, we have that t = 2.543 hours, so that is the time needed to the bacteria count reaching 8019.

4 0
4 years ago
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