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4 years ago

How many cups is in 1 liter

Mathematics

1 answer:

sdas [7]4 years ago

5 0

There are approximately 4 cups in one liter (or if you want the exact its 4.22675)

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Is 1/9 closer to 0 or closer 1/2

egoroff_w [7]

1/9 is closer to 0

I help I helped please leave thanks

6 0

3 years ago

Read 2 more answers

Plz help when you see this

kolezko [41]

Answer:

126

Step-by-step explanation:

angle ZWY = 180 - 90 - 63 = 27

Base on the given information, the length of XW is same with the length of ZW, which means they have the same angle.

Quadrangle has angle of 360

360(quadrangle) - 27(ZWY)- 27(XWY) - 90(WZY) - 90(WXY)

= 126

5 0

2 years ago

Rachel can buy 18 eggs for $1.49 or 12 eggs for $1.09. Which is the better buy?

Mnenie [13.5K]

<span> 1.09/12=0.091 18 eggs is a better buy</span>

3 0

4 years ago

Please help asap, brainliest,thanks, and 50 points. Thank you soooo much! <3

Anuta_ua [19.1K]

Answers:

1) $x^{8} y^{8}$

2) $y^{3} \sqrt{y}$

3) $5x^{4} \sqrt{6}$

4) $\sqrt{7}$

5) $\frac{\sqrt{z}}{z}$

Step-by-step explanation:

1) $\sqrt{x^{16} y^{36}}$

Rewriting the expression:

$(x^{16} y^{36})^{\frac{1}{2}}$

Multiplying the exponents:

$x^{\frac{16}{2}} y^{\frac{36}{2}}$

Simplifying:

$x^{8} y^{8}$

2) $\sqrt{y^{7}}$

Rewriting the expression:

$\sqrt{y^{6} y}=(y^{6} y)^{\frac{1}{2}}$

Multiplying the exponents:

$y^{\frac{6}{2}} y^{\frac{1}{2}}$

Simplifying:

$y^{3} y^{\frac{1}{2}}=y^{3} \sqrt{y}$

3) $\sqrt{150 x^{8}}$

Rewriting the expression:

$\sqrt{(6)(25) x^{8}}$

Since $\sqrt{25}=5$ :

$5x^{4}\sqrt{6}$

4) $\frac{7}{\sqrt{7}}$

Multiplying numerator and denominator by $\sqrt{7}$ :

$\frac{7}{\sqrt{7}} (\frac{\sqrt{7}}{\sqrt{7}})=\frac{7}{7\sqrt{7}}$

Simplifying:

$\sqrt{7}$

5) $\frac{5z}{\sqrt{25 z^{3}}}$

Rewriting the expression:

$\frac{5z}{5z \sqrt{z}}$

Simplifying:

$\frac{1}{\sqrt{z}}$

Since we do not want the square root in the denominator, we can multiply numerator and denominator by $\sqrt{z}$ :

$\frac{1}{\sqrt{z}}(\frac{\sqrt{z}}{\sqrt{z}})$

Finally:

$\frac{\sqrt{z}}{z}$

3 0

4 years ago

Suppose there are 10 identical items. 10 items are selected one by one with replacement. What is the probability that a particul

Sophie [7]

Answer:

Step-by-step explanation:

Lets look at the first pick. There are 9 items that can be choosen, one that cannot. So the chance to not pick the one is 9/10.

All the other attempts are the same and have 9/10 chance. (as replacement happens)

Now these events are independent of eachother so the combined chance is

(9/10)^10

For the formula:

Number of items: n

One pick is: (n-1)/n

N pick together is [(n-1)/n]^n

6 0

3 years ago