ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
11 5/8 in = 11.625 in
9 3/4in = 9.75 in
10 1/2 in= 10.5 in
11.625+9.75+10.5= 31.875in
To find the average divide the total of inches by the amount of pieces there are to find the average:
31.875 / 3 = 10.625in
2
42 ÷ 2 = 21
16 ÷ 2 = 8
Let's try the other factors of 42...
42 ÷ 6 = 7
16 ÷ 6 = 2.66
No...
42 ÷ 7 = 6
16 ÷ 7 = 2 2/7
No...
42 ÷ 14 = 3
16 ÷ 14 = 1.1428
No...
