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Nonamiya [84]
3 years ago
14

Help me answer this question please

Mathematics
1 answer:
Rudik [331]3 years ago
8 0
Its a little blurry and i need glasses so can u take another pic

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what is the length of the diagonal of a non-regulation tennis court with length 20 feet and width 15 feet?
Semmy [17]

Answer:

25 feet

Step-by-step explanation:

Basically that non-regulation tennis court is a rectangle. You want to know the length of the diagonal. If you draw it on paper, you'll see that this then become 2 triangles... of which you have 2 sides, and are seeking the hypotenuse.  So....

H² = A² + B²

H² = 20² + 15² = 400 + 225 = 625

H = 25 feet.

6 0
3 years ago
Read 2 more answers
help asap im in a quiz, please show some sort of proof. and please dont say,¨ the answer is in the photo, and then send me a lin
Setler [38]
The answer would be D i think because if the two angles are to equal 72, and one of the angles equals 42, 72-42= 30. to find x, you’d do 30/6 which equals 5. so x=5 and the angle measure would be 30
4 0
3 years ago
Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to
RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

5 0
3 years ago
Jessica wants to calculate her grade in her accounting class.she has four test grades (82, 65, 71, and 77) and a homework grade
Aleks04 [339]

To solve the problem, get the percentage of each test by multiplying the score and the percentage then add it all up:


82 * .25 (highest test grade) + 65* .15 (lowest test grade) + 71*.20 (each test remaining) + 77*.20 (each test remaining) + 92*.20 (homework grade)


= 20.5 + 9.75 + 14.2 + 15.4 + 18.4 = 78.25 or 78% in whole number

3 0
4 years ago
Which of the following expressions is equivalent to 3 m ( m − 2 ) − ( m ^2 + 1 ) ?
leonid [27]

Answer:

uh

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
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