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steposvetlana [31]
2 years ago
5

How do I solve tan(62) = 12/x?

Mathematics
1 answer:
notsponge [240]2 years ago
3 0

Answer:

x = 6/31 = 0.194

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (62)-(12/x)=0

Step by step solution :

Step  1  :

           12

Simplify   ——

           x

Equation at the end of step  1  :

       12

 62 -  ——  = 0

       x

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  x  as the denominator :

          62     62 • x

    62 =  ——  =  ——————

          1        x  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

62 • x - (12)     62x - 12

—————————————  =  ————————

      x              x    

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  62x - 12  =   2 • (31x - 6)

Equation at the end of step  3  :

 2 • (31x - 6)

 —————————————  = 0

       x      

Step  4  :

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 2•(31x-6)

 ————————— • x = 0 • x

     x    

Now, on the left hand side, the  x  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  2  •  (31x-6)  = 0

Equations which are never true :

4.2      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.3      Solve  :    31x-6 = 0

Add  6  to both sides of the equation :

                     31x = 6

Divide both sides of the equation by 31:

                    x = 6/31 = 0.194

Answer :

                  x = 6/31 = 0.194

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.......…............
Nookie1986 [14]

Answer:

\frac{7}{8} \div \frac{1}{2} = \frac{7}{4}

Step-by-step explanation:

Here we are given four equations and we have to find the equation that gives the number of half inches that are in \frac{7}{8} inches.

To find how many half inches i.e. \frac{1}{2} inches are there in \frac{7}{8} inches we have to divide \frac{7}{8} by \frac{1}{2}.

So, the equation that will give the result is \frac{7}{8} \div \frac{1}{2} = \frac{7}{8} \times \frac{2}{1} = \frac{7}{4} (Answer)

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It costs $198.00 to buy beef to make 300 meatballs. What will the cost be<br> to make 120 meatballs?
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3 0
3 years ago
Plant A: A graph has time (weeks) on the x-axis, and height (inches) on the y-axis. A line goes through points (0, 3), (1, 4.8),
butalik [34]

Answer:

The correct option is;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks

Step-by-step explanation:

The parameters given are;

Plant A:

Weeks,    Height

0,               3

1,                4.8

2,               6.6

3,               8.4

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant A per week is therefore;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{8.4 - 3 }{3 - 0} = \dfrac{5.4}{3} = 1.8 \ inches/week

Therefore we have;

H = 1.8 × t + 3

At week 6,

H = 3 + 6×1.8 = 13.8 inches

Plant B

Weeks,    Height

2,               7.3

3,               8.7

4,               10.1

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant B per week is given as follows;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{10.1 - 7.3 }{4 - 2} = \dfrac{2.8}{2} = 1.4 \ inches/week

Therefore we have;

When t = 2, H = 7.3 hence, 7.3 = 2 × 1.4 + H₀

Where:

H₀ = H at t = 0

H₀ = 7.3 - 2 × 1.4 = 4.5

At week 6 we have;

H = 4.5 + 6×1.4 = 12.9 inches

Which indicates that Plant A will be 0.9 inches taller than Plant B at week 6.

The correct option is therefore;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks.

5 0
3 years ago
Read 2 more answers
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