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Nina [5.8K]
3 years ago
11

Jean sold cupcakes and cookies yesterday. Each cupcake sold for $2.25 and each cookie sold for $0.50. At the end of the day, Jea

n had sold $42.75 worth of cookies and cupcakes. If she sold 40 cupcakes and cookies combined, how many cupcakes were sold and how many cookies were sold?
Mathematics
1 answer:
slega [8]3 years ago
4 0

Answer:number of cupcakes sold is 13

Number of cookies sold is 27

Step-by-step explanation:

Let x represent the number of cupcakes that Jane sold.

Let y represent the number of cookies that Jane sold.

Each cupcake sold for $2.25 and each cookie sold for $0.50. At the end of the day, Jean had sold $42.75 worth of cookies and cupcakes.

This means that

2.25x + 0.5y = 42.75 - - - - - - - - - -1

she sold 40 cupcakes and cookies combined, it means that

x + y = 40

Substituting x = 40 - y into equation 1, it becomes

2.25(40 - y) + 0.5y = 42.75

90 - 2.25y + 0.5y = 42.75

- 2.25y + 0.5y = 42.75 - 90

- 1.75y = - 47.25

y = - 47.35/-1.75

y = 27

x = 40 - y

x = 40-27 = 13

.

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Answer:  

<em>a.  The system of equations that models the situation is....</em>

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Suppose, the amount of 80/20 mixture is  x pounds and the amount of 50/50 mixture is  y pounds.

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