First, a line that is parallel, means a line that has the same slope as the original. To find the slope of the original equation, we have to solve for y.
-2x+3y=-6
3y=2x-6
y=2/3x-2
From this equation, we can see that the slope of the line is 2/3. For every 2 units you go up, you move three units over.
Now we need to use the point (-2,0) to find the equation of the parallel line.
y-y=m(x-x)
Plug in the point coordinates and the slope, and solve for the final equation of the line.
y-0=2/3(x+2)
y=2/3x+ 4/3
Answer: B sorry if im wrong
Step-by-step explanation:
Answer:
The length of rope is 20.0 ft . Hence, <u>option (1) </u> is correct.
Step-by-step explanation:
In the figure below AB represents pole having height 10 ft and AC represents the rope that is from the top of pole to the ground. BC represent the ground distance from base of tower to the rope.
The rope and the ground form a 30 degree angle that is the angle between BC and AC is 30°.
In right angled triangle ABC with right angle at B.
Since we have to find the length of rope that is the value of side AC.
Using trigonometric ratios


Putting values,

We know, 

On solving we get,
AC= 20.0 ft
Thus, the length of rope is 20.0 ft
Hence, <u>option (1)</u> is correct.
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Let


because that is the range of the inverse cosine funcition.
Also,
![\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\ \mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}](https://tex.z-dn.net/?f=%5Cmathsf%7Bcos%5C%2C%5Ctheta%3Dcos%5C%21%5Cleft%5Bcos%5E%7B-1%7D%5C%21%5Cleft%28%5Cdfrac%7B4%7D%7B5%7D%5Cright%29%5Cright%5D%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7Bcos%5C%2C%5Ctheta%3D%5Cdfrac%7B4%7D%7B5%7D%7D%5C%5C%5C%5C%5C%5C%20%5Cmathsf%7B5%5C%2Ccos%5C%2C%5Ctheta%3D4%7D)
Square both sides and apply the fundamental trigonometric identity:



But

which means

lies either in the 1st or the 2nd quadrant. So

is a positive number:
![\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\ \therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}](https://tex.z-dn.net/?f=%5Cmathsf%7Bsin%5C%2C%5Ctheta%3D%5Cdfrac%7B3%7D%7B5%7D%7D%5C%5C%5C%5C%5C%5C%0A%5Ctherefore~~%5Cmathsf%7Bsin%5C%21%5Cleft%5Bcos%5E%7B-1%7D%5C%21%5Cleft%28%5Cdfrac%7B4%7D%7B5%7D%5Cright%29%5Cright%5D%3D%5Cdfrac%7B3%7D%7B5%7D%5Cqquad%5Cquad%5Ccheckmark%7D)
I hope this helps. =)
Tags: <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>
Hello,
The answer is
<span>B. Y-intercept of (0, −1), starts down on the left, gets closer to y = −3 on the right
Hope this helps</span>