1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tju [1.3M]
3 years ago
8

Find the area of each sector shown (the shaded section)

Mathematics
1 answer:
mihalych1998 [28]3 years ago
4 0

Answer:

The area of the sector (shaded section) is 29.51 m^{2}.

Step-by-step explanation:

Area of a sector = (θ ÷ 360) \pir^{2}

where θ is the central angle of the sector, and r is the radius of the circle.

From the diagram give, diameter of the circle is 26 m. So that;

r = \frac{diameter}{2}

 = \frac{26}{2} = 13 m

θ = 360 - (180 + 160)

  = 360 - 340

  = 20^{o}

Thus,

area of the given sector = \frac{20}{360} x \frac{22}{7} x (13)^{2}

                                        = \frac{20}{360} x x \frac{22}{7} x 169

                                         = 29.5079

The area of the sector (shaded section) is 29.51 m^{2}.

You might be interested in
What is the equation of a line that is parallel to -2x+3y=-6 and passes through the point (-2,0)
mr_godi [17]
First, a line that is parallel, means a line that has the same slope as the original. To find the slope of the original equation, we have to solve for y.
-2x+3y=-6
3y=2x-6
y=2/3x-2
From this equation, we can see that the slope of the line is 2/3. For every 2 units you go up, you move three units over.

Now we need to use the point (-2,0) to find the equation of the parallel line. 
y-y=m(x-x)

Plug in the point coordinates and the slope, and solve for the final equation of the line.
y-0=2/3(x+2)
y=2/3x+ 4/3
4 0
3 years ago
PLSS HELPPP WITH MATH
ANTONII [103]

Answer: B sorry if im wrong

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A 10 ft pole has a support rope that extends from the top of the pole to the ground. The rope and the ground form a 30 degree an
mr Goodwill [35]

Answer:

The length of rope is 20.0 ft . Hence, <u>option (1) </u> is correct.

Step-by-step explanation:

In the figure below AB represents pole having height 10 ft  and AC represents the rope that is from the top of pole to the ground. BC represent the ground distance from base of tower to the rope.

The rope and the ground form a 30 degree angle that is the angle between BC and AC is 30°.

In right angled triangle ABC with right angle at B.

Since we have to find the length of rope that is the value of side AC.

Using trigonometric ratios

\sin C=\frac{\text{perpendicular}}{\text{hypotenuse}}

\sin C=\frac{AB}{AC}

Putting values,

\sin 30^\circ} =\frac{10}{AC}

We know, \sin 30^\circ}=\frac{1}{2}

\frac{1}{2} =\frac{10}{AC}

On solving we get,

AC= 20.0 ft

Thus, the length of rope is 20.0 ft

Hence, <u>option (1)</u> is correct.

8 0
3 years ago
Read 2 more answers
Find the exact value of sin(cos^-1(4/5))
boyakko [2]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2762144

_______________


Let  \mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}


\mathsf{0\le \theta\le\pi,}  because that is the range of the inverse cosine funcition.


Also,

\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\&#10;\mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}


Square both sides and apply the fundamental trigonometric identity:

\mathsf{(5\,cos\,\theta)^2=4^2}\\\\&#10;\mathsf{5^2\,cos^2\,\theta=4^2}\\\\&#10;\mathsf{25\,cos^2\,\theta=16\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\&#10;\mathsf{25\cdot (1-sin^2\,\theta)=16}

\mathsf{25-25\,sin^2\,\theta=16}\\\\&#10;\mathsf{25-16=25\,sin^2\,\theta}\\\\&#10;\mathsf{9=25\,sin^2\,\theta}\\\\&#10;\mathsf{sin^2\,\theta=\dfrac{9}{25}}&#10;

\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{9}{25}}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{3^2}{5^2}}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\dfrac{3}{5}}


But \mathsf{0\le \theta\le\pi,} which means \theta lies either in the 1st or the 2nd quadrant. So \mathsf{sin\,\theta} is a positive number:

\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\&#10;\therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}


I hope this helps. =)


Tags:  <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>

3 0
3 years ago
Read 2 more answers
50 POINTS 
Tasya [4]
Hello,


The answer is

<span>B. Y-intercept of (0, −1), starts down on the left, gets closer to y = −3 on the right

Hope this helps</span>
5 0
3 years ago
Other questions:
  • Trump or Joe Biden?​
    15·2 answers
  • What quadrilateral does not belong with a square, reactangle &amp; a parallelogram?
    5·2 answers
  • In Δ LMN,  ∠N  is a right angle, LM = 76, and MN = 40. What is m ∠M ?
    15·2 answers
  • HELPPPP FASTTTTTT PLZZZ
    12·1 answer
  • Which of the following numbers does not have
    14·1 answer
  • What is 1m x1000 tgggggggggggggggggggggggggggggggg
    5·1 answer
  • What what is the answer? why is answer for picture ?​
    10·2 answers
  • Given the endpoints of a segment, find the length of each segment.<br>A (-3, 7) and B (-5, 2)​
    15·1 answer
  • WILL GIVW BRANLIEST DUE TODAY thank you&gt;&gt;&gt;Three meals per day are provided by the hotel. The hotel will charge a total
    7·2 answers
  • If LM = 9, MN = 6x, and LN = 9x, what is LN?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!