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Molodets [167]
3 years ago
13

The temperature is -2 if the temperature rises by 15 what is the new temperature​

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0

- 2 + 15 = 13

That is the new temperature.

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Question in the picture
mart [117]

I will find x, so 4x-4=180, so 4x=184, so x=46

Sorry if i answered wrong I don't understand what it is asking for.

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3 years ago
So in this equation x + 2y= -8<br> would the slope be 1 ?
Slav-nsk [51]
X + 2y = -8

Subtract 'x' to both sides:

2y = -x - 8

DIvide 2 to both sides:

y = -1/2x - 4

Slope is -1/2, not 1.
7 0
3 years ago
Read 2 more answers
Find the prime factors of 60 by dividing by prime numbers.​
Mars2501 [29]

Let's start with the smallest prime number 2

60/2 = 30

Divide that result over 2

30/2 = 15

We can't divide this by 2 because 15/2 = 7.5 isn't a whole number

Let's move onto 3

15/3 = 5

The result is a prime number, so we stop.

The values we divided as denominators were: {2, 2, 3}

We add the result 5 to the set to completely list all of the prime factors of 60

The prime factorization would be

<h3>60 = 2*2*3*5</h3>

which is the same as saying

<h3>60 = 2^2*3*5</h3>
7 0
2 years ago
Coffee Tea
Lelu [443]

Answer:

A larger percentage of people in New York prefer coffee

3 0
2 years ago
A filter filled with liquid is in the shape of a vertex-down cone with a height of 9 inches and a diameter of 6 inches at its op
Alina [70]

Answer: Level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

Step-by-step explanation:

Since we have given that

Height = 9 inches

Diameter = 6 inches

Radius = 3 inches

So, \dfrac{r}{h}=\dfrac{3}{9}=\dfrac{1}{3}\\\\r=\dfrac{1}{3}h

Volume of cone is given by

V=\dfrac{1}{3}\pi r^2h\\\\V=\dfrac{1}{3}\pi \dfrac{1}{9}h^2\times h\\\\V=\dfrac{1}{27}\pi h^3

By differentiating with respect to time t, we get that

\dfrac{dv}{dt}=\dfrac{1}{27}\pi \times 3\times h^2\dfrac{dh}{dt}=\dfrac{1}{9}\pi h^2\dfrac{dh}{dt}

Now,  the liquid drips out the bottom of the filter at the constant rate of 4 cubic inches per second, ie \dfrac{dv}{dt}=-4\ in^3

and h = 2 inches deep.

-4=\dfrac{1}{9}\times \pi\times (2)^2\dfrac{dh}{dt}\\\\-9\pi =\dfrac{dh}{dt}\\\\-28.28=\dfrac{dh}{dt}

Hence, level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

7 0
3 years ago
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