Can u show the graph so i can answer
Answer:
-3e/2
Step-by-step explanation:
Answer: neither graph A nor graph B, because, even though both curves are above the horizontal axis, neither graph has an area of 1
Step-by-step explanation:
<em>Areas under the graphs:</em>
<em />
<u>Graph A</u>
<u />
<u>Graph B</u>
<u />
As neither of these graphs have an area of 1, neither of them are density curves.
<h3>
Answers:</h3>
- u+v = <3,12>
- w+g = <7,0>
- g-z = <2,4>
- v-u = <9,4>
- y+v = <7,9>
- u+v+y = <4,13>
===================================================
Explanation:
Problem 1
If we had the two vectors u = <a,b> and v = <c,d>, then adding them gives us
u+v = <a+c,b+d>
The corresponding coordinates pair up and add together.
In this case we have
u = <-3,4>
v = <6,8>
So,
u+v = <-3+6,4+8>
u+v = <3,12>
---------------------
Problem 2
We follow the same idea as the previous problem.
w = <8,-1>
g = <-1,1>
w+g = <8+(-1),-1+1>
w+g = <7,0>
---------------------
Problem 3
Similar to addition, subtracting vectors has us subtract the corresponding coordinates.
The general template is:
u = <a,b>
v = <c,d>
u-v = <a-c,b-d>
With this in mind, we can say the following:
g = <-1,1>
z = <-3,-3>
g-z = <-1-(-3),1-(-3)>
g-z = <-1+3,1+3>
g-z = <2,4>
---------------------
Problem 4
Follow the same idea as problem 3 above.
v = <6,8>
u = <-3,4>
v-u = <6-(-3),8-4>
v-u = <6+3,8-4>
v-u = <9,4>
---------------------
Problem 5
Refer to problem 1.
y = <1,1>
v = <6,8>
y+v = <1+6,1+8>
y+v = <7,9>
---------------------
Problem 6
u = <-3,4>
h = v+y = y+v = <7,9>
u+v+y = u + h
u+v+y = <-3,4> + <7,9>
u+v+y = <-3+7,4+9>
u+v+y = <4,13>
Notice how I built off the result of problem 5 when I used h = v+y. The vector v+y is the same as y+v because the order of addition doesn't matter. Also, the idea mentioned in problem 1 can be extended for more than two vectors.
The answer would be <span>-10.125</span>
