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igomit [66]
3 years ago
8

A 208-long road is divided into 16 parts of equal length.Mr.Ward paints a 4-meter-long strip in each part.How many total meters

are not painted in the 208 meters of road?
Mathematics
2 answers:
Readme [11.4K]3 years ago
6 0
208 % 16 = 13
13 - 4 = meters not painted in a part = 9
9 × 16 (parts) = 144 meters of road not painted
Yuki888 [10]3 years ago
6 0

Answer

Find out the how many total meters are not painted in the 208 meters of road .

To prove

Let us assume that the total meters are not painted in the 208 meters of road be x.

As given

A 208-long road is divided into 16 parts of equal length.

Each\ road\ length\ when\ divided\ into\ 16\ equal\ parts = \frac{208}{16}

Each road length when divided into 16 equal parts = 13 meters

As given

Mr.Ward paints a 4-meter-long strip in each part.

Mr.Ward not paints  in each part =  13 - 4

                                                      = 9 meters

Thus

Total meters are not painted in the 208 meters of road = 9 × 16

                                                                                            = 144 meters

Therefore 144 meters are not painted in the 208 meters of road .




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