2y=x+6 2y-x=6 how do i solve following the system of equations

1 answer:

7 0

$2y = x + 6 \\ \\ 1. \: 2y - 6 = x \\ 2. \: x = 2y - 6 \\ \\ \\ 2y - x = 6 \\ \\ 1. \: - x = 6 - 2y \\ 2. \: x = - 6 + 2y \\ 3. \: x = 2y - 6$

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After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?

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pishuonlain [190]

We are given the following information concerning the three production machines;

$\begin{gathered} Of\text{ the total production;} \\ A=55\text{ \%}=0.55 \\ B=25\text{ \%}=0.25 \\ C=20\text{ \%}=0.20 \end{gathered}$

Also, we are given the percentage of defective output as follows;

$\begin{gathered} A=3.5\text{ \%}=0.035 \\ B=4.5\text{ \%}=0.045 \\ C=5.5\text{ \%}=0.055 \end{gathered}$

Therefore, if an item is selected randomly, the probability that the item is defective would be;

$\begin{gathered} P\lbrack defective\rbrack=(0.55\times0.035)+(0.25\times0.045)+(0.20\times0.055) \\ P\lbrack\text{defective\rbrack}=0.01925+0.01125+0.011 \\ P\lbrack\text{defective\rbrack}=0.0415 \end{gathered}$

ANSWER:

The probability that the item is defective would be 0.0415

6 0

1 year ago